| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.35 |
| Score | 0% | 67% |
10 members of a bridal party need transported to a wedding reception but there are only 3 2-passenger taxis available to take them. How many will need to find other transportation?
| 4 | |
| 5 | |
| 3 | |
| 2 |
There are 3 2-passenger taxis available so that's 3 x 2 = 6 total seats. There are 10 people needing transportation leaving 10 - 6 = 4 who will have to find other transportation.
Convert 0.0002856 to scientific notation.
| 2.856 x 10-4 | |
| 28.56 x 10-5 | |
| 2.856 x 104 | |
| 2.856 x 10-3 |
A number in scientific notation has the format 0.000 x 10exponent. To convert to scientific notation, move the decimal point to the right or the left until the number is a decimal between 1 and 10. The exponent of the 10 is the number of places you moved the decimal point and is positive if you moved the decimal point to the left and negative if you moved it to the right:
0.0002856 in scientific notation is 2.856 x 10-4
What is \( 8 \)\( \sqrt{20} \) - \( 3 \)\( \sqrt{5} \)
| 13\( \sqrt{5} \) | |
| 24\( \sqrt{5} \) | |
| 24\( \sqrt{20} \) | |
| 5\( \sqrt{21} \) |
To subtract these radicals together their radicands must be the same:
8\( \sqrt{20} \) - 3\( \sqrt{5} \)
8\( \sqrt{4 \times 5} \) - 3\( \sqrt{5} \)
8\( \sqrt{2^2 \times 5} \) - 3\( \sqrt{5} \)
(8)(2)\( \sqrt{5} \) - 3\( \sqrt{5} \)
16\( \sqrt{5} \) - 3\( \sqrt{5} \)
Now that the radicands are identical, you can subtract them:
16\( \sqrt{5} \) - 3\( \sqrt{5} \)If a car travels 90 miles in 6 hours, what is the average speed?
| 40 mph | |
| 15 mph | |
| 25 mph | |
| 55 mph |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)a(b + c) = ab + ac defines which of the following?
distributive property for multiplication |
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distributive property for division |
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commutative property for multiplication |
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commutative property for division |
The distributive property for multiplication helps in solving expressions like a(b + c). It specifies that the result of multiplying one number by the sum or difference of two numbers can be obtained by multiplying each number individually and then totaling the results: a(b + c) = ab + ac. For example, 4(10-5) = (4 x 10) - (4 x 5) = 40 - 20 = 20.