| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.94 |
| Score | 0% | 59% |
A bread recipe calls for 3\(\frac{5}{8}\) cups of flour. If you only have 1\(\frac{3}{4}\) cups, how much more flour is needed?
| 3 cups | |
| 1\(\frac{7}{8}\) cups | |
| 2\(\frac{5}{8}\) cups | |
| 2 cups |
The amount of flour you need is (3\(\frac{5}{8}\) - 1\(\frac{3}{4}\)) cups. Rewrite the quantities so they share a common denominator and subtract:
(\( \frac{29}{8} \) - \( \frac{14}{8} \)) cups
\( \frac{15}{8} \) cups
1\(\frac{7}{8}\) cups
A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 30% off." If Damon buys two shirts, each with a regular price of $48, how much will he pay for both shirts?
| $69.60 | |
| $81.60 | |
| $14.40 | |
| $67.20 |
By buying two shirts, Damon will save $48 x \( \frac{30}{100} \) = \( \frac{$48 x 30}{100} \) = \( \frac{$1440}{100} \) = $14.40 on the second shirt.
So, his total cost will be
$48.00 + ($48.00 - $14.40)
$48.00 + $33.60
$81.60
What is \( \frac{2}{9} \) ÷ \( \frac{3}{7} \)?
| \(\frac{4}{15}\) | |
| \(\frac{14}{27}\) | |
| \(\frac{4}{63}\) | |
| 4\(\frac{2}{3}\) |
To divide fractions, invert the second fraction and then multiply:
\( \frac{2}{9} \) ÷ \( \frac{3}{7} \) = \( \frac{2}{9} \) x \( \frac{7}{3} \)
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{2}{9} \) x \( \frac{7}{3} \) = \( \frac{2 x 7}{9 x 3} \) = \( \frac{14}{27} \) = \(\frac{14}{27}\)
If a mayor is elected with 77% of the votes cast and 86% of a town's 19,000 voters cast a vote, how many votes did the mayor receive?
| 9,967 | |
| 10,294 | |
| 13,889 | |
| 12,582 |
If 86% of the town's 19,000 voters cast ballots the number of votes cast is:
(\( \frac{86}{100} \)) x 19,000 = \( \frac{1,634,000}{100} \) = 16,340
The mayor got 77% of the votes cast which is:
(\( \frac{77}{100} \)) x 16,340 = \( \frac{1,258,180}{100} \) = 12,582 votes.
\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?
distributive property for division |
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commutative property for multiplication |
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distributive property for multiplication |
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commutative property for division |
The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).