| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.57 |
| Score | 0% | 71% |
What is the greatest common factor of 80 and 20?
| 10 | |
| 9 | |
| 6 | |
| 20 |
The factors of 80 are [1, 2, 4, 5, 8, 10, 16, 20, 40, 80] and the factors of 20 are [1, 2, 4, 5, 10, 20]. They share 6 factors [1, 2, 4, 5, 10, 20] making 20 the greatest factor 80 and 20 have in common.
Solve for \( \frac{2!}{6!} \)
| \( \frac{1}{9} \) | |
| \( \frac{1}{6} \) | |
| \( \frac{1}{504} \) | |
| \( \frac{1}{360} \) |
A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:
\( \frac{2!}{6!} \)
\( \frac{2 \times 1}{6 \times 5 \times 4 \times 3 \times 2 \times 1} \)
\( \frac{1}{6 \times 5 \times 4 \times 3} \)
\( \frac{1}{360} \)
Christine scored 97% on her final exam. If each question was worth 4 points and there were 360 possible points on the exam, how many questions did Christine answer correctly?
| 91 | |
| 75 | |
| 84 | |
| 87 |
Christine scored 97% on the test meaning she earned 97% of the possible points on the test. There were 360 possible points on the test so she earned 360 x 0.97 = 348 points. Each question is worth 4 points so she got \( \frac{348}{4} \) = 87 questions right.
Which of the following is a mixed number?
\({5 \over 7} \) |
|
\({a \over 5} \) |
|
\({7 \over 5} \) |
|
\(1 {2 \over 5} \) |
A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.
Which of the following is an improper fraction?
\({2 \over 5} \) |
|
\(1 {2 \over 5} \) |
|
\({7 \over 5} \) |
|
\({a \over 5} \) |
A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.