| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.53 |
| Score | 0% | 71% |
Which of the following is a mixed number?
\({7 \over 5} \) |
|
\({a \over 5} \) |
|
\(1 {2 \over 5} \) |
|
\({5 \over 7} \) |
A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.
Roger loaned Monica $1,500 at an annual interest rate of 3%. If no payments are made, what is the total amount owed at the end of the first year?
| $1,545 | |
| $1,620 | |
| $1,515 | |
| $1,575 |
The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:
interest = annual interest rate x loan amount
i = (\( \frac{6}{100} \)) x $1,500
i = 0.03 x $1,500
No payments were made so the total amount due is the original amount + the accumulated interest:
total = $1,500 + $45In a class of 25 students, 15 are taking German and 13 are taking Spanish. Of the students studying German or Spanish, 9 are taking both courses. How many students are not enrolled in either course?
| 18 | |
| 16 | |
| 6 | |
| 21 |
The number of students taking German or Spanish is 15 + 13 = 28. Of that group of 28, 9 are taking both languages so they've been counted twice (once in the German group and once in the Spanish group). Subtracting them out leaves 28 - 9 = 19 who are taking at least one language. 25 - 19 = 6 students who are not taking either language.
Solve for \( \frac{3!}{6!} \)
| 3024 | |
| 6720 | |
| 56 | |
| \( \frac{1}{120} \) |
A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:
\( \frac{3!}{6!} \)
\( \frac{3 \times 2 \times 1}{6 \times 5 \times 4 \times 3 \times 2 \times 1} \)
\( \frac{1}{6 \times 5 \times 4} \)
\( \frac{1}{120} \)
What is \( \frac{3}{7} \) ÷ \( \frac{1}{9} \)?
| \(\frac{1}{12}\) | |
| \(\frac{1}{3}\) | |
| 3\(\frac{6}{7}\) | |
| \(\frac{1}{5}\) |
To divide fractions, invert the second fraction and then multiply:
\( \frac{3}{7} \) ÷ \( \frac{1}{9} \) = \( \frac{3}{7} \) x \( \frac{9}{1} \)
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{3}{7} \) x \( \frac{9}{1} \) = \( \frac{3 x 9}{7 x 1} \) = \( \frac{27}{7} \) = 3\(\frac{6}{7}\)