| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.30 |
| Score | 0% | 66% |
A tiger in a zoo has consumed 84 pounds of food in 6 days. If the tiger continues to eat at the same rate, in how many more days will its total food consumtion be 126 pounds?
| 7 | |
| 8 | |
| 3 | |
| 4 |
If the tiger has consumed 84 pounds of food in 6 days that's \( \frac{84}{6} \) = 14 pounds of food per day. The tiger needs to consume 126 - 84 = 42 more pounds of food to reach 126 pounds total. At 14 pounds of food per day that's \( \frac{42}{14} \) = 3 more days.
What is (x2)3?
| x-1 | |
| x6 | |
| 3x2 | |
| x |
To raise a term with an exponent to another exponent, retain the base and multiply the exponents:
(x2)3Which of these numbers is a factor of 24?
| 28 | |
| 8 | |
| 4 | |
| 9 |
The factors of a number are all positive integers that divide evenly into the number. The factors of 24 are 1, 2, 3, 4, 6, 8, 12, 24.
7 members of a bridal party need transported to a wedding reception but there are only 3 2-passenger taxis available to take them. How many will need to find other transportation?
| 8 | |
| 6 | |
| 1 | |
| 4 |
There are 3 2-passenger taxis available so that's 3 x 2 = 6 total seats. There are 7 people needing transportation leaving 7 - 6 = 1 who will have to find other transportation.
Solve 2 + (3 + 5) ÷ 4 x 2 - 52
| 1\(\frac{1}{3}\) | |
| \(\frac{4}{5}\) | |
| 1\(\frac{1}{5}\) | |
| -19 |
Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):
2 + (3 + 5) ÷ 4 x 2 - 52
P: 2 + (8) ÷ 4 x 2 - 52
E: 2 + 8 ÷ 4 x 2 - 25
MD: 2 + \( \frac{8}{4} \) x 2 - 25
MD: 2 + \( \frac{16}{4} \) - 25
AS: \( \frac{8}{4} \) + \( \frac{16}{4} \) - 25
AS: \( \frac{24}{4} \) - 25
AS: \( \frac{24 - 100}{4} \)
\( \frac{-76}{4} \)
-19