ASVAB Arithmetic Reasoning Practice Test 409536 Results

Your Results Global Average
Questions 5 5
Correct 0 3.19
Score 0% 64%

Review

1

What is \( \frac{-8c^9}{2c^2} \)?

60% Answer Correctly
-\(\frac{1}{4}\)c11
-4c-7
-4c7
-4c11

Solution

To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:

\( \frac{-8c^9}{2c^2} \)
\( \frac{-8}{2} \) c(9 - 2)
-4c7


2

A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 50% off." If Frank buys two shirts, each with a regular price of $31, how much money will he save?

70% Answer Correctly
$12.40
$9.30
$15.50
$10.85

Solution

By buying two shirts, Frank will save $31 x \( \frac{50}{100} \) = \( \frac{$31 x 50}{100} \) = \( \frac{$1550}{100} \) = $15.50 on the second shirt.


3

What is -4b5 + b5?

66% Answer Correctly
-3b5
-5b-5
-3b25
-3b10

Solution

To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so add the coefficients and retain the base and exponent:

-4b5 + 1b5
(-4 + 1)b5
-3b5


4

Frank loaned Roger $1,200 at an annual interest rate of 5%. If no payments are made, what is the interest owed on this loan at the end of the first year?

74% Answer Correctly
$48
$60
$24
$88

Solution

The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:

interest = annual interest rate x loan amount

i = (\( \frac{6}{100} \)) x $1,200
i = 0.05 x $1,200
i = $60


5

A machine in a factory has an error rate of 3 parts per 100. The machine normally runs 24 hours a day and produces 8 parts per hour. Yesterday the machine was shut down for 9 hours for maintenance.

How many error-free parts did the machine produce yesterday?

48% Answer Correctly
125.5
105.8
98.9
116.4

Solution

The hourly error rate for this machine is the error rate in parts per 100 multiplied by the number of parts produced per hour:

\( \frac{3}{100} \) x 8 = \( \frac{3 \times 8}{100} \) = \( \frac{24}{100} \) = 0.24 errors per hour

So, in an average hour, the machine will produce 8 - 0.24 = 7.76 error free parts.

The machine ran for 24 - 9 = 15 hours yesterday so you would expect that 15 x 7.76 = 116.4 error free parts were produced yesterday.