| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.95 |
| Score | 0% | 59% |
Solve for \( \frac{4!}{3!} \)
| \( \frac{1}{5} \) | |
| 8 | |
| 4 | |
| 9 |
A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:
\( \frac{4!}{3!} \)
\( \frac{4 \times 3 \times 2 \times 1}{3 \times 2 \times 1} \)
\( \frac{4}{1} \)
4
A bread recipe calls for 1\(\frac{7}{8}\) cups of flour. If you only have \(\frac{7}{8}\) cup, how much more flour is needed?
| 1\(\frac{1}{2}\) cups | |
| 1 cups | |
| 3\(\frac{3}{8}\) cups | |
| 2\(\frac{1}{4}\) cups |
The amount of flour you need is (1\(\frac{7}{8}\) - \(\frac{7}{8}\)) cups. Rewrite the quantities so they share a common denominator and subtract:
(\( \frac{15}{8} \) - \( \frac{7}{8} \)) cups
\( \frac{8}{8} \) cups
1 cups
Christine scored 75% on her final exam. If each question was worth 3 points and there were 180 possible points on the exam, how many questions did Christine answer correctly?
| 48 | |
| 34 | |
| 58 | |
| 45 |
Christine scored 75% on the test meaning she earned 75% of the possible points on the test. There were 180 possible points on the test so she earned 180 x 0.75 = 135 points. Each question is worth 3 points so she got \( \frac{135}{3} \) = 45 questions right.
What is 6\( \sqrt{7} \) x 2\( \sqrt{5} \)?
| 12\( \sqrt{12} \) | |
| 12\( \sqrt{7} \) | |
| 8\( \sqrt{35} \) | |
| 12\( \sqrt{35} \) |
To multiply terms with radicals, multiply the coefficients and radicands separately:
6\( \sqrt{7} \) x 2\( \sqrt{5} \)
(6 x 2)\( \sqrt{7 \times 5} \)
12\( \sqrt{35} \)
What is the next number in this sequence: 1, 5, 13, 25, 41, __________ ?
| 59 | |
| 61 | |
| 64 | |
| 67 |
The equation for this sequence is:
an = an-1 + 4(n - 1)
where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:
a6 = a5 + 4(6 - 1)
a6 = 41 + 4(5)
a6 = 61