| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.02 |
| Score | 0% | 60% |
If the ratio of home fans to visiting fans in a crowd is 5:1 and all 41,000 seats in a stadium are filled, how many home fans are in attendance?
| 37,500 | |
| 31,200 | |
| 24,800 | |
| 34,167 |
A ratio of 5:1 means that there are 5 home fans for every one visiting fan. So, of every 6 fans, 5 are home fans and \( \frac{5}{6} \) of every fan in the stadium is a home fan:
41,000 fans x \( \frac{5}{6} \) = \( \frac{205000}{6} \) = 34,167 fans.
What is \( 2 \)\( \sqrt{12} \) + \( 3 \)\( \sqrt{3} \)
| 6\( \sqrt{12} \) | |
| 6\( \sqrt{3} \) | |
| 7\( \sqrt{3} \) | |
| 5\( \sqrt{12} \) |
To add these radicals together their radicands must be the same:
2\( \sqrt{12} \) + 3\( \sqrt{3} \)
2\( \sqrt{4 \times 3} \) + 3\( \sqrt{3} \)
2\( \sqrt{2^2 \times 3} \) + 3\( \sqrt{3} \)
(2)(2)\( \sqrt{3} \) + 3\( \sqrt{3} \)
4\( \sqrt{3} \) + 3\( \sqrt{3} \)
Now that the radicands are identical, you can add them together:
4\( \sqrt{3} \) + 3\( \sqrt{3} \)A factor is a positive __________ that divides evenly into a given number.
improper fraction |
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mixed number |
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fraction |
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integer |
A factor is a positive integer that divides evenly into a given number. For example, the factors of 8 are 1, 2, 4, and 8.
How many 12-passenger vans will it take to drive all 81 members of the football team to an away game?
| 9 vans | |
| 15 vans | |
| 7 vans | |
| 3 vans |
Calculate the number of vans needed by dividing the number of people that need transported by the capacity of one van:
vans = \( \frac{81}{12} \) = 6\(\frac{3}{4}\)
So, it will take 6 full vans and one partially full van to transport the entire team making a total of 7 vans.
If all of a roofing company's 15 workers are required to staff 5 roofing crews, how many workers need to be added during the busy season in order to send 8 complete crews out on jobs?
| 9 | |
| 11 | |
| 10 | |
| 12 |
In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 15 workers at the company now and that's enough to staff 5 crews so there are \( \frac{15}{5} \) = 3 workers on a crew. 8 crews are needed for the busy season which, at 3 workers per crew, means that the roofing company will need 8 x 3 = 24 total workers to staff the crews during the busy season. The company already employs 15 workers so they need to add 24 - 15 = 9 new staff for the busy season.