ASVAB Arithmetic Reasoning Practice Test 410463 Results

Your Results Global Average
Questions 5 5
Correct 0 3.28
Score 0% 66%

Review

1

What is \( \frac{2}{8} \) x \( \frac{3}{8} \)?

72% Answer Correctly
\(\frac{3}{32}\)
\(\frac{2}{7}\)
\(\frac{3}{4}\)
\(\frac{1}{4}\)

Solution

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{2}{8} \) x \( \frac{3}{8} \) = \( \frac{2 x 3}{8 x 8} \) = \( \frac{6}{64} \) = \(\frac{3}{32}\)


2

Which of the following is not a prime number?

64% Answer Correctly

9

5

2

7


Solution

A prime number is an integer greater than 1 that has no factors other than 1 and itself. Examples of prime numbers include 2, 3, 5, 7, and 11.


3

If \(\left|a\right| = 7\), which of the following best describes a?

67% Answer Correctly

a = -7

none of these is correct

a = 7

a = 7 or a = -7


Solution

The absolute value is the positive magnitude of a particular number or variable and is indicated by two vertical lines: \(\left|-5\right| = 5\). In the case of a variable absolute value (\(\left|a\right| = 5\)) the value of a can be either positive or negative (a = -5 or a = 5).


4

A circular logo is enlarged to fit the lid of a jar. The new diameter is 75% larger than the original. By what percentage has the area of the logo increased?

50% Answer Correctly
37\(\frac{1}{2}\)%
32\(\frac{1}{2}\)%
25%
20%

Solution

The area of a circle is given by the formula A = πr2 where r is the radius of the circle. The radius of a circle is its diameter divided by two so A = π(\( \frac{d}{2} \))2. If the diameter of the logo increases by 75% the radius (and, consequently, the total area) increases by \( \frac{75\text{%}}{2} \) = 37\(\frac{1}{2}\)%


5

What is the least common multiple of 5 and 7?

72% Answer Correctly
7
35
31
34

Solution

The first few multiples of 5 are [5, 10, 15, 20, 25, 30, 35, 40, 45, 50] and the first few multiples of 7 are [7, 14, 21, 28, 35, 42, 49, 56, 63, 70]. The first few multiples they share are [35, 70] making 35 the smallest multiple 5 and 7 have in common.