ASVAB Arithmetic Reasoning Practice Test 411028 Results

Your Results Global Average
Questions 5 5
Correct 0 3.43
Score 0% 69%

Review

1

In a class of 33 students, 7 are taking German and 14 are taking Spanish. Of the students studying German or Spanish, 3 are taking both courses. How many students are not enrolled in either course?

63% Answer Correctly
18
11
15
28

Solution

The number of students taking German or Spanish is 7 + 14 = 21. Of that group of 21, 3 are taking both languages so they've been counted twice (once in the German group and once in the Spanish group). Subtracting them out leaves 21 - 3 = 18 who are taking at least one language. 33 - 18 = 15 students who are not taking either language.


2

Find the average of the following numbers: 17, 11, 15, 13.

74% Answer Correctly
14
11
9
12

Solution

To find the average of these 4 numbers add them together then divide by 4:

\( \frac{17 + 11 + 15 + 13}{4} \) = \( \frac{56}{4} \) = 14


3

Solve for \( \frac{3!}{6!} \)

67% Answer Correctly
42
\( \frac{1}{336} \)
\( \frac{1}{120} \)
\( \frac{1}{8} \)

Solution

A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:

\( \frac{3!}{6!} \)
\( \frac{3 \times 2 \times 1}{6 \times 5 \times 4 \times 3 \times 2 \times 1} \)
\( \frac{1}{6 \times 5 \times 4} \)
\( \frac{1}{120} \)


4

Which of these numbers is a factor of 32?

68% Answer Correctly
17
2
22
5

Solution

The factors of a number are all positive integers that divide evenly into the number. The factors of 32 are 1, 2, 4, 8, 16, 32.


5

Which of the following is an improper fraction?

70% Answer Correctly

\({2 \over 5} \)

\({7 \over 5} \)

\({a \over 5} \)

\(1 {2 \over 5} \)


Solution

A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.