| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.12 |
| Score | 0% | 62% |
A factor is a positive __________ that divides evenly into a given number.
improper fraction |
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integer |
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fraction |
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mixed number |
A factor is a positive integer that divides evenly into a given number. For example, the factors of 8 are 1, 2, 4, and 8.
What is the next number in this sequence: 1, 3, 7, 13, 21, __________ ?
| 27 | |
| 35 | |
| 37 | |
| 31 |
The equation for this sequence is:
an = an-1 + 2(n - 1)
where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:
a6 = a5 + 2(6 - 1)
a6 = 21 + 2(5)
a6 = 31
On average, the center for a basketball team hits 45% of his shots while a guard on the same team hits 60% of his shots. If the guard takes 20 shots during a game, how many shots will the center have to take to score as many points as the guard assuming each shot is worth the same number of points?
| 22 | |
| 29 | |
| 25 | |
| 27 |
guard shots made = shots taken x \( \frac{\text{% made}}{100} \) = 20 x \( \frac{60}{100} \) = \( \frac{60 x 20}{100} \) = \( \frac{1200}{100} \) = 12 shots
The center makes 45% of his shots so he'll have to take:
shots made = shots taken x \( \frac{\text{% made}}{100} \)
shots taken = \( \frac{\text{shots taken}}{\frac{\text{% made}}{100}} \)
to make as many shots as the guard. Plugging in values for the center gives us:
center shots taken = \( \frac{12}{\frac{45}{100}} \) = 12 x \( \frac{100}{45} \) = \( \frac{12 x 100}{45} \) = \( \frac{1200}{45} \) = 27 shots
to make the same number of shots as the guard and thus score the same number of points.
What is (z4)4?
| z8 | |
| 4z4 | |
| z16 | |
| z0 |
To raise a term with an exponent to another exponent, retain the base and multiply the exponents:
(z4)4What is 2\( \sqrt{6} \) x 7\( \sqrt{7} \)?
| 14\( \sqrt{7} \) | |
| 14\( \sqrt{42} \) | |
| 9\( \sqrt{42} \) | |
| 14\( \sqrt{6} \) |
To multiply terms with radicals, multiply the coefficients and radicands separately:
2\( \sqrt{6} \) x 7\( \sqrt{7} \)
(2 x 7)\( \sqrt{6 \times 7} \)
14\( \sqrt{42} \)