ASVAB Arithmetic Reasoning Practice Test 412966 Results

Your Results Global Average
Questions 5 5
Correct 0 3.08
Score 0% 62%

Review

1

a(b + c) = ab + ac defines which of the following?

75% Answer Correctly

commutative property for division

distributive property for division

commutative property for multiplication

distributive property for multiplication


Solution

The distributive property for multiplication helps in solving expressions like a(b + c). It specifies that the result of multiplying one number by the sum or difference of two numbers can be obtained by multiplying each number individually and then totaling the results: a(b + c) = ab + ac. For example, 4(10-5) = (4 x 10) - (4 x 5) = 40 - 20 = 20.


2

Convert c-3 to remove the negative exponent.

68% Answer Correctly
\( \frac{1}{c^3} \)
\( \frac{1}{c^{-3}} \)
\( \frac{-3}{-c} \)
\( \frac{-1}{-3c} \)

Solution

To convert a negative exponent to a positive exponent, calculate the positive exponent then take the reciprocal.


3

Which of the following is an improper fraction?

70% Answer Correctly

\(1 {2 \over 5} \)

\({2 \over 5} \)

\({7 \over 5} \)

\({a \over 5} \)


Solution

A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.


4

The __________ is the smallest positive integer that is a multiple of two or more integers.

56% Answer Correctly

absolute value

least common multiple

greatest common factor

least common factor


Solution

The least common multiple (LCM) is the smallest positive integer that is a multiple of two or more integers.


5

What is \( 3 \)\( \sqrt{48} \) - \( 6 \)\( \sqrt{3} \)

39% Answer Correctly
18\( \sqrt{16} \)
-3\( \sqrt{-7} \)
6\( \sqrt{3} \)
-3\( \sqrt{3} \)

Solution

To subtract these radicals together their radicands must be the same:

3\( \sqrt{48} \) - 6\( \sqrt{3} \)
3\( \sqrt{16 \times 3} \) - 6\( \sqrt{3} \)
3\( \sqrt{4^2 \times 3} \) - 6\( \sqrt{3} \)
(3)(4)\( \sqrt{3} \) - 6\( \sqrt{3} \)
12\( \sqrt{3} \) - 6\( \sqrt{3} \)

Now that the radicands are identical, you can subtract them:

12\( \sqrt{3} \) - 6\( \sqrt{3} \)
(12 - 6)\( \sqrt{3} \)
6\( \sqrt{3} \)