| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.08 |
| Score | 0% | 62% |
a(b + c) = ab + ac defines which of the following?
commutative property for division |
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distributive property for division |
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commutative property for multiplication |
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distributive property for multiplication |
The distributive property for multiplication helps in solving expressions like a(b + c). It specifies that the result of multiplying one number by the sum or difference of two numbers can be obtained by multiplying each number individually and then totaling the results: a(b + c) = ab + ac. For example, 4(10-5) = (4 x 10) - (4 x 5) = 40 - 20 = 20.
Convert c-3 to remove the negative exponent.
| \( \frac{1}{c^3} \) | |
| \( \frac{1}{c^{-3}} \) | |
| \( \frac{-3}{-c} \) | |
| \( \frac{-1}{-3c} \) |
To convert a negative exponent to a positive exponent, calculate the positive exponent then take the reciprocal.
Which of the following is an improper fraction?
\(1 {2 \over 5} \) |
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\({2 \over 5} \) |
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\({7 \over 5} \) |
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\({a \over 5} \) |
A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.
The __________ is the smallest positive integer that is a multiple of two or more integers.
absolute value |
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least common multiple |
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greatest common factor |
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least common factor |
The least common multiple (LCM) is the smallest positive integer that is a multiple of two or more integers.
What is \( 3 \)\( \sqrt{48} \) - \( 6 \)\( \sqrt{3} \)
| 18\( \sqrt{16} \) | |
| -3\( \sqrt{-7} \) | |
| 6\( \sqrt{3} \) | |
| -3\( \sqrt{3} \) |
To subtract these radicals together their radicands must be the same:
3\( \sqrt{48} \) - 6\( \sqrt{3} \)
3\( \sqrt{16 \times 3} \) - 6\( \sqrt{3} \)
3\( \sqrt{4^2 \times 3} \) - 6\( \sqrt{3} \)
(3)(4)\( \sqrt{3} \) - 6\( \sqrt{3} \)
12\( \sqrt{3} \) - 6\( \sqrt{3} \)
Now that the radicands are identical, you can subtract them:
12\( \sqrt{3} \) - 6\( \sqrt{3} \)