The first few multiples of 4 are [4, 8, 12, 16, 20, 24, 28, 32, 36, 40] and the first few multiples of 6 are [6, 12, 18, 24, 30, 36, 42, 48, 54, 60]. The first few multiples they share are [12, 24, 36, 48, 60] making 12 the smallest multiple 4 and 6 have in common.

The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 24 meters so the equation becomes: 2w + 2h = 24.

Putting these two equations together and solving for width (w):

2w + 2h = 24
w + h = \( \frac{24}{2} \)
w + h = 12
w = 12 - h

From the question we know that h = 2w so substituting 2w for h gives us:

w = 12 - 2w
3w = 12
w = \( \frac{12}{3} \)
w = 4

Since h = 2w that makes h = (2 x 4) = 8 and the area = h x w = 4 x 8 = 32 m²

The factors of 44 are [1, 2, 4, 11, 22, 44] and the factors of 44 are [1, 2, 4, 11, 22, 44]. They share 6 factors [1, 2, 4, 11, 22, 44] making 44 the greatest factor 44 and 44 have in common.

By buying two shirts, Monty will save $21 x \( \frac{30}{100} \) = \( \frac{$21 x 30}{100} \) = \( \frac{$630}{100} \) = $6.30 on the second shirt.

So, his total cost will be
$21.00 + ($21.00 - $6.30)
$21.00 + $14.70
$35.70

You have 12 out of the total of 250 raffle tickets sold so you have a (\( \frac{12}{250} \)) x 100 = \( \frac{12 \times 100}{250} \) = \( \frac{1200}{250} \) = 5% chance to win the raffle.