| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.59 |
| Score | 0% | 72% |
Simplify \( \frac{32}{76} \).
| \( \frac{8}{19} \) | |
| \( \frac{1}{3} \) | |
| \( \frac{6}{11} \) | |
| \( \frac{7}{12} \) |
To simplify this fraction, first find the greatest common factor between them. The factors of 32 are [1, 2, 4, 8, 16, 32] and the factors of 76 are [1, 2, 4, 19, 38, 76]. They share 3 factors [1, 2, 4] making 4 their greatest common factor (GCF).
Next, divide both numerator and denominator by the GCF:
\( \frac{32}{76} \) = \( \frac{\frac{32}{4}}{\frac{76}{4}} \) = \( \frac{8}{19} \)
Convert 0.0006454 to scientific notation.
| 0.645 x 10-3 | |
| 6.454 x 10-4 | |
| 64.54 x 10-5 | |
| 6.454 x 105 |
A number in scientific notation has the format 0.000 x 10exponent. To convert to scientific notation, move the decimal point to the right or the left until the number is a decimal between 1 and 10. The exponent of the 10 is the number of places you moved the decimal point and is positive if you moved the decimal point to the left and negative if you moved it to the right:
0.0006454 in scientific notation is 6.454 x 10-4
How many 16-passenger vans will it take to drive all 35 members of the football team to an away game?
| 6 vans | |
| 14 vans | |
| 8 vans | |
| 3 vans |
Calculate the number of vans needed by dividing the number of people that need transported by the capacity of one van:
vans = \( \frac{35}{16} \) = 2\(\frac{3}{16}\)
So, it will take 2 full vans and one partially full van to transport the entire team making a total of 3 vans.
What is -7x6 - 9x6?
| -16x6 | |
| 2x6 | |
| 2x-12 | |
| 2x12 |
To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so subtract the coefficients and retain the base and exponent:
-7x6 - 9x6
(-7 - 9)x6
-16x6
Convert z-3 to remove the negative exponent.
| \( \frac{-1}{-3z^{3}} \) | |
| \( \frac{1}{z^3} \) | |
| \( \frac{-3}{z} \) | |
| \( \frac{1}{z^{-3}} \) |
To convert a negative exponent to a positive exponent, calculate the positive exponent then take the reciprocal.