| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.95 |
| Score | 0% | 59% |
If a car travels 60 miles in 4 hours, what is the average speed?
| 25 mph | |
| 50 mph | |
| 15 mph | |
| 70 mph |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)How many 2\(\frac{1}{2}\) gallon cans worth of fuel would you need to pour into an empty 25 gallon tank to fill it exactly halfway?
| 4 | |
| 10 | |
| 2 | |
| 5 |
To fill a 25 gallon tank exactly halfway you'll need 12\(\frac{1}{2}\) gallons of fuel. Each fuel can holds 2\(\frac{1}{2}\) gallons so:
cans = \( \frac{12\frac{1}{2} \text{ gallons}}{2\frac{1}{2} \text{ gallons}} \) = 5
What is \( 6 \)\( \sqrt{8} \) - \( 2 \)\( \sqrt{2} \)
| 4\( \sqrt{0} \) | |
| 4\( \sqrt{4} \) | |
| 4\( \sqrt{8} \) | |
| 10\( \sqrt{2} \) |
To subtract these radicals together their radicands must be the same:
6\( \sqrt{8} \) - 2\( \sqrt{2} \)
6\( \sqrt{4 \times 2} \) - 2\( \sqrt{2} \)
6\( \sqrt{2^2 \times 2} \) - 2\( \sqrt{2} \)
(6)(2)\( \sqrt{2} \) - 2\( \sqrt{2} \)
12\( \sqrt{2} \) - 2\( \sqrt{2} \)
Now that the radicands are identical, you can subtract them:
12\( \sqrt{2} \) - 2\( \sqrt{2} \)A machine in a factory has an error rate of 9 parts per 100. The machine normally runs 24 hours a day and produces 8 parts per hour. Yesterday the machine was shut down for 4 hours for maintenance.
How many error-free parts did the machine produce yesterday?
| 96.9 | |
| 177.7 | |
| 145.6 | |
| 115.9 |
The hourly error rate for this machine is the error rate in parts per 100 multiplied by the number of parts produced per hour:
\( \frac{9}{100} \) x 8 = \( \frac{9 \times 8}{100} \) = \( \frac{72}{100} \) = 0.72 errors per hour
So, in an average hour, the machine will produce 8 - 0.72 = 7.28 error free parts.
The machine ran for 24 - 4 = 20 hours yesterday so you would expect that 20 x 7.28 = 145.6 error free parts were produced yesterday.
Charlie loaned Christine $700 at an annual interest rate of 7%. If no payments are made, what is the total amount owed at the end of the first year?
| $742 | |
| $749 | |
| $756 | |
| $763 |
The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:
interest = annual interest rate x loan amount
i = (\( \frac{6}{100} \)) x $700
i = 0.07 x $700
No payments were made so the total amount due is the original amount + the accumulated interest:
total = $700 + $49