| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.47 |
| Score | 0% | 69% |
Solve for \( \frac{5!}{3!} \)
| \( \frac{1}{840} \) | |
| 1680 | |
| 56 | |
| 20 |
A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:
\( \frac{5!}{3!} \)
\( \frac{5 \times 4 \times 3 \times 2 \times 1}{3 \times 2 \times 1} \)
\( \frac{5 \times 4}{1} \)
\( 5 \times 4 \)
20
What is the distance in miles of a trip that takes 2 hours at an average speed of 60 miles per hour?
| 330 miles | |
| 120 miles | |
| 125 miles | |
| 420 miles |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)Solving for distance:
distance = \( \text{speed} \times \text{time} \)
distance = \( 60mph \times 2h \)
120 miles
Solve 4 + (3 + 4) ÷ 4 x 4 - 52
| 1\(\frac{1}{4}\) | |
| -14 | |
| 1\(\frac{1}{2}\) | |
| \(\frac{5}{7}\) |
Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):
4 + (3 + 4) ÷ 4 x 4 - 52
P: 4 + (7) ÷ 4 x 4 - 52
E: 4 + 7 ÷ 4 x 4 - 25
MD: 4 + \( \frac{7}{4} \) x 4 - 25
MD: 4 + \( \frac{28}{4} \) - 25
AS: \( \frac{16}{4} \) + \( \frac{28}{4} \) - 25
AS: \( \frac{44}{4} \) - 25
AS: \( \frac{44 - 100}{4} \)
\( \frac{-56}{4} \)
-14
How many hours does it take a car to travel 140 miles at an average speed of 70 miles per hour?
| 1 hour | |
| 2 hours | |
| 3 hours | |
| 7 hours |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)Solving for time:
time = \( \frac{\text{distance}}{\text{speed}} \)
time = \( \frac{140mi}{70mph} \)
2 hours
The total water usage for a city is 15,000 gallons each day. Of that total, 22% is for personal use and 49% is for industrial use. How many more gallons of water each day is consumed for industrial use over personal use?
| 6,800 | |
| 1,250 | |
| 4,550 | |
| 4,050 |
49% of the water consumption is industrial use and 22% is personal use so (49% - 22%) = 27% more water is used for industrial purposes. 15,000 gallons are consumed daily so industry consumes \( \frac{27}{100} \) x 15,000 gallons = 4,050 gallons.