| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.04 |
| Score | 0% | 61% |
What is the greatest common factor of 72 and 52?
| 28 | |
| 6 | |
| 49 | |
| 4 |
The factors of 72 are [1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, 72] and the factors of 52 are [1, 2, 4, 13, 26, 52]. They share 3 factors [1, 2, 4] making 4 the greatest factor 72 and 52 have in common.
On average, the center for a basketball team hits 40% of his shots while a guard on the same team hits 45% of his shots. If the guard takes 30 shots during a game, how many shots will the center have to take to score as many points as the guard assuming each shot is worth the same number of points?
| 45 | |
| 48 | |
| 57 | |
| 33 |
guard shots made = shots taken x \( \frac{\text{% made}}{100} \) = 30 x \( \frac{45}{100} \) = \( \frac{45 x 30}{100} \) = \( \frac{1350}{100} \) = 13 shots
The center makes 40% of his shots so he'll have to take:
shots made = shots taken x \( \frac{\text{% made}}{100} \)
shots taken = \( \frac{\text{shots taken}}{\frac{\text{% made}}{100}} \)
to make as many shots as the guard. Plugging in values for the center gives us:
center shots taken = \( \frac{13}{\frac{40}{100}} \) = 13 x \( \frac{100}{40} \) = \( \frac{13 x 100}{40} \) = \( \frac{1300}{40} \) = 33 shots
to make the same number of shots as the guard and thus score the same number of points.
How many 11-passenger vans will it take to drive all 58 members of the football team to an away game?
| 4 vans | |
| 3 vans | |
| 5 vans | |
| 6 vans |
Calculate the number of vans needed by dividing the number of people that need transported by the capacity of one van:
vans = \( \frac{58}{11} \) = 5\(\frac{3}{11}\)
So, it will take 5 full vans and one partially full van to transport the entire team making a total of 6 vans.
A bread recipe calls for 3\(\frac{1}{8}\) cups of flour. If you only have 1 cup, how much more flour is needed?
| 1 cups | |
| 1\(\frac{7}{8}\) cups | |
| 3\(\frac{1}{2}\) cups | |
| 2\(\frac{1}{8}\) cups |
The amount of flour you need is (3\(\frac{1}{8}\) - 1) cups. Rewrite the quantities so they share a common denominator and subtract:
(\( \frac{25}{8} \) - \( \frac{8}{8} \)) cups
\( \frac{17}{8} \) cups
2\(\frac{1}{8}\) cups
What is \( 9 \)\( \sqrt{125} \) - \( 3 \)\( \sqrt{5} \)
| 6\( \sqrt{125} \) | |
| 27\( \sqrt{625} \) | |
| 42\( \sqrt{5} \) | |
| 6\( \sqrt{25} \) |
To subtract these radicals together their radicands must be the same:
9\( \sqrt{125} \) - 3\( \sqrt{5} \)
9\( \sqrt{25 \times 5} \) - 3\( \sqrt{5} \)
9\( \sqrt{5^2 \times 5} \) - 3\( \sqrt{5} \)
(9)(5)\( \sqrt{5} \) - 3\( \sqrt{5} \)
45\( \sqrt{5} \) - 3\( \sqrt{5} \)
Now that the radicands are identical, you can subtract them:
45\( \sqrt{5} \) - 3\( \sqrt{5} \)