ASVAB Arithmetic Reasoning Practice Test 417698 Results

Your Results Global Average
Questions 5 5
Correct 0 3.41
Score 0% 68%

Review

1

Solve for \( \frac{3!}{2!} \)

67% Answer Correctly
72
\( \frac{1}{210} \)
3
4

Solution

A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:

\( \frac{3!}{2!} \)
\( \frac{3 \times 2 \times 1}{2 \times 1} \)
\( \frac{3}{1} \)
3


2

What is \( \frac{-7x^5}{2x^3} \)?

60% Answer Correctly
-3\(\frac{1}{2}\)x2
-\(\frac{2}{7}\)x-2
-3\(\frac{1}{2}\)x\(\frac{3}{5}\)
-3\(\frac{1}{2}\)x1\(\frac{2}{3}\)

Solution

To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:

\( \frac{-7x^5}{2x^3} \)
\( \frac{-7}{2} \) x(5 - 3)
-3\(\frac{1}{2}\)x2


3

What is the least common multiple of 3 and 9?

72% Answer Correctly
9
4
5
22

Solution

The first few multiples of 3 are [3, 6, 9, 12, 15, 18, 21, 24, 27, 30] and the first few multiples of 9 are [9, 18, 27, 36, 45, 54, 63, 72, 81, 90]. The first few multiples they share are [9, 18, 27, 36, 45] making 9 the smallest multiple 3 and 9 have in common.


4

What is \( \sqrt{\frac{81}{49}} \)?

70% Answer Correctly
2\(\frac{1}{2}\)
\(\frac{4}{5}\)
\(\frac{5}{9}\)
1\(\frac{2}{7}\)

Solution

To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:

\( \sqrt{\frac{81}{49}} \)
\( \frac{\sqrt{81}}{\sqrt{49}} \)
\( \frac{\sqrt{9^2}}{\sqrt{7^2}} \)
\( \frac{9}{7} \)
1\(\frac{2}{7}\)


5

What is \( \frac{3}{5} \) x \( \frac{2}{8} \)?

72% Answer Correctly
1\(\frac{1}{5}\)
\(\frac{4}{49}\)
\(\frac{3}{20}\)
\(\frac{4}{63}\)

Solution

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{3}{5} \) x \( \frac{2}{8} \) = \( \frac{3 x 2}{5 x 8} \) = \( \frac{6}{40} \) = \(\frac{3}{20}\)