| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.07 |
| Score | 0% | 61% |
Solve for \( \frac{2!}{4!} \)
| 60480 | |
| \( \frac{1}{12} \) | |
| 6720 | |
| \( \frac{1}{120} \) |
A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:
\( \frac{2!}{4!} \)
\( \frac{2 \times 1}{4 \times 3 \times 2 \times 1} \)
\( \frac{1}{4 \times 3} \)
\( \frac{1}{12} \)
On average, the center for a basketball team hits 30% of his shots while a guard on the same team hits 45% of his shots. If the guard takes 10 shots during a game, how many shots will the center have to take to score as many points as the guard assuming each shot is worth the same number of points?
| 13 | |
| 7 | |
| 10 | |
| 9 |
guard shots made = shots taken x \( \frac{\text{% made}}{100} \) = 10 x \( \frac{45}{100} \) = \( \frac{45 x 10}{100} \) = \( \frac{450}{100} \) = 4 shots
The center makes 30% of his shots so he'll have to take:
shots made = shots taken x \( \frac{\text{% made}}{100} \)
shots taken = \( \frac{\text{shots taken}}{\frac{\text{% made}}{100}} \)
to make as many shots as the guard. Plugging in values for the center gives us:
center shots taken = \( \frac{4}{\frac{30}{100}} \) = 4 x \( \frac{100}{30} \) = \( \frac{4 x 100}{30} \) = \( \frac{400}{30} \) = 13 shots
to make the same number of shots as the guard and thus score the same number of points.
| 1 | |
| 7.2 | |
| 2.7 | |
| 5.4 |
1
Damon loaned Frank $900 at an annual interest rate of 1%. If no payments are made, what is the interest owed on this loan at the end of the first year?
| $80 | |
| $91 | |
| $15 | |
| $9 |
The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:
interest = annual interest rate x loan amount
i = (\( \frac{6}{100} \)) x $900
i = 0.01 x $900
i = $9
What is \( \sqrt{\frac{36}{49}} \)?
| 2 | |
| \(\frac{6}{7}\) | |
| 4 | |
| 1\(\frac{4}{5}\) |
To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:
\( \sqrt{\frac{36}{49}} \)
\( \frac{\sqrt{36}}{\sqrt{49}} \)
\( \frac{\sqrt{6^2}}{\sqrt{7^2}} \)
\(\frac{6}{7}\)