| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.06 |
| Score | 0% | 61% |
On average, the center for a basketball team hits 25% of his shots while a guard on the same team hits 30% of his shots. If the guard takes 25 shots during a game, how many shots will the center have to take to score as many points as the guard assuming each shot is worth the same number of points?
| 16 | |
| 13 | |
| 28 | |
| 18 |
guard shots made = shots taken x \( \frac{\text{% made}}{100} \) = 25 x \( \frac{30}{100} \) = \( \frac{30 x 25}{100} \) = \( \frac{750}{100} \) = 7 shots
The center makes 25% of his shots so he'll have to take:
shots made = shots taken x \( \frac{\text{% made}}{100} \)
shots taken = \( \frac{\text{shots taken}}{\frac{\text{% made}}{100}} \)
to make as many shots as the guard. Plugging in values for the center gives us:
center shots taken = \( \frac{7}{\frac{25}{100}} \) = 7 x \( \frac{100}{25} \) = \( \frac{7 x 100}{25} \) = \( \frac{700}{25} \) = 28 shots
to make the same number of shots as the guard and thus score the same number of points.
Which of the following is an improper fraction?
\(1 {2 \over 5} \) |
|
\({7 \over 5} \) |
|
\({a \over 5} \) |
|
\({2 \over 5} \) |
A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.
Solve 2 + (4 + 4) ÷ 5 x 4 - 42
| \(\frac{2}{3}\) | |
| 1 | |
| -7\(\frac{3}{5}\) | |
| \(\frac{4}{7}\) |
Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):
2 + (4 + 4) ÷ 5 x 4 - 42
P: 2 + (8) ÷ 5 x 4 - 42
E: 2 + 8 ÷ 5 x 4 - 16
MD: 2 + \( \frac{8}{5} \) x 4 - 16
MD: 2 + \( \frac{32}{5} \) - 16
AS: \( \frac{10}{5} \) + \( \frac{32}{5} \) - 16
AS: \( \frac{42}{5} \) - 16
AS: \( \frac{42 - 80}{5} \)
\( \frac{-38}{5} \)
-7\(\frac{3}{5}\)
What is \( \frac{14\sqrt{18}}{7\sqrt{6}} \)?
| \(\frac{1}{2}\) \( \sqrt{\frac{1}{3}} \) | |
| 2 \( \sqrt{3} \) | |
| 3 \( \sqrt{\frac{1}{2}} \) | |
| \(\frac{1}{2}\) \( \sqrt{3} \) |
To divide terms with radicals, divide the coefficients and radicands separately:
\( \frac{14\sqrt{18}}{7\sqrt{6}} \)
\( \frac{14}{7} \) \( \sqrt{\frac{18}{6}} \)
2 \( \sqrt{3} \)
A triathlon course includes a 200m swim, a 20.4km bike ride, and a 9.6km run. What is the total length of the race course?
| 49.7km | |
| 30.2km | |
| 39.3km | |
| 45.8km |
To add these distances, they must share the same unit so first you need to first convert the swim distance from meters (m) to kilometers (km) before adding it to the bike and run distances which are already in km. To convert 200 meters to kilometers, divide the distance by 1000 to get 0.2km then add the remaining distances:
total distance = swim + bike + run
total distance = 0.2km + 20.4km + 9.6km
total distance = 30.2km