ASVAB Arithmetic Reasoning Practice Test 424520 Results

Your Results Global Average
Questions 5 5
Correct 0 3.85
Score 0% 77%

Review

1

What is -b3 - 7b3?

71% Answer Correctly
8b-3
6b3
6b-6
-8b3

Solution

To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so subtract the coefficients and retain the base and exponent:

-1b3 - 7b3
(-1 - 7)b3
-8b3


2

What is \( \frac{16\sqrt{10}}{8\sqrt{2}} \)?

71% Answer Correctly
2 \( \sqrt{5} \)
5 \( \sqrt{\frac{1}{2}} \)
\(\frac{1}{5}\) \( \sqrt{\frac{1}{2}} \)
\(\frac{1}{5}\) \( \sqrt{2} \)

Solution

To divide terms with radicals, divide the coefficients and radicands separately:

\( \frac{16\sqrt{10}}{8\sqrt{2}} \)
\( \frac{16}{8} \) \( \sqrt{\frac{10}{2}} \)
2 \( \sqrt{5} \)


3

Roger loaned Ezra $200 at an annual interest rate of 5%. If no payments are made, what is the interest owed on this loan at the end of the first year?

74% Answer Correctly
$24
$13
$10
$88

Solution

The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:

interest = annual interest rate x loan amount

i = (\( \frac{6}{100} \)) x $200
i = 0.05 x $200
i = $10


4

Simplify \( \frac{32}{52} \).

77% Answer Correctly
\( \frac{5}{9} \)
\( \frac{5}{19} \)
\( \frac{8}{13} \)
\( \frac{8}{17} \)

Solution

To simplify this fraction, first find the greatest common factor between them. The factors of 32 are [1, 2, 4, 8, 16, 32] and the factors of 52 are [1, 2, 4, 13, 26, 52]. They share 3 factors [1, 2, 4] making 4 their greatest common factor (GCF).

Next, divide both numerator and denominator by the GCF:

\( \frac{32}{52} \) = \( \frac{\frac{32}{4}}{\frac{52}{4}} \) = \( \frac{8}{13} \)


5

What is the next number in this sequence: 1, 2, 3, 4, 5, __________ ?

92% Answer Correctly
2
6
7
4

Solution

The equation for this sequence is:

an = an-1 + 1

where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:

a6 = a5 + 1
a6 = 5 + 1
a6 = 6