| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.47 |
| Score | 0% | 69% |
What is (c3)2?
| c | |
| c-1 | |
| c6 | |
| 2c3 |
To raise a term with an exponent to another exponent, retain the base and multiply the exponents:
(c3)2What is \( \frac{4}{6} \) x \( \frac{1}{5} \)?
| \(\frac{3}{28}\) | |
| \(\frac{2}{7}\) | |
| \(\frac{4}{5}\) | |
| \(\frac{2}{15}\) |
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{4}{6} \) x \( \frac{1}{5} \) = \( \frac{4 x 1}{6 x 5} \) = \( \frac{4}{30} \) = \(\frac{2}{15}\)
In a class of 26 students, 11 are taking German and 12 are taking Spanish. Of the students studying German or Spanish, 7 are taking both courses. How many students are not enrolled in either course?
| 14 | |
| 18 | |
| 21 | |
| 10 |
The number of students taking German or Spanish is 11 + 12 = 23. Of that group of 23, 7 are taking both languages so they've been counted twice (once in the German group and once in the Spanish group). Subtracting them out leaves 23 - 7 = 16 who are taking at least one language. 26 - 16 = 10 students who are not taking either language.
What is \( \frac{7}{4} \) - \( \frac{4}{8} \)?
| \( \frac{3}{8} \) | |
| 2 \( \frac{2}{8} \) | |
| 1\(\frac{1}{4}\) | |
| 1 \( \frac{1}{8} \) |
To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 4 are [4, 8, 12, 16, 20, 24, 28, 32, 36, 40] and the first few multiples of 8 are [8, 16, 24, 32, 40, 48, 56, 64, 72, 80]. The first few multiples they share are [8, 16, 24, 32, 40] making 8 the smallest multiple 4 and 8 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{7 x 2}{4 x 2} \) - \( \frac{4 x 1}{8 x 1} \)
\( \frac{14}{8} \) - \( \frac{4}{8} \)
Now, because the fractions share a common denominator, you can subtract them:
\( \frac{14 - 4}{8} \) = \( \frac{10}{8} \) = 1\(\frac{1}{4}\)
What is -8a7 - 6a7?
| -2a-14 | |
| -14a7 | |
| -2a14 | |
| 14a-7 |
To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so subtract the coefficients and retain the base and exponent:
-8a7 - 6a7
(-8 - 6)a7
-14a7