| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.81 |
| Score | 0% | 56% |
A sports card collection contains football, baseball, and basketball cards. If the ratio of football to baseball cards is 3 to 2 and the ratio of baseball to basketball cards is 3 to 1, what is the ratio of football to basketball cards?
| 3:1 | |
| 5:8 | |
| 9:1 | |
| 9:2 |
The ratio of football cards to baseball cards is 3:2 and the ratio of baseball cards to basketball cards is 3:1. To solve this problem, we need the baseball card side of each ratio to be equal so we need to rewrite the ratios in terms of a common number of baseball cards. (Think of this like finding the common denominator when adding fractions.) The ratio of football to baseball cards can also be written as 9:6 and the ratio of baseball cards to basketball cards as 6:2. So, the ratio of football cards to basketball cards is football:baseball, baseball:basketball or 9:6, 6:2 which reduces to 9:2.
If a mayor is elected with 86% of the votes cast and 84% of a town's 37,000 voters cast a vote, how many votes did the mayor receive?
| 27,040 | |
| 16,472 | |
| 26,729 | |
| 22,688 |
If 84% of the town's 37,000 voters cast ballots the number of votes cast is:
(\( \frac{84}{100} \)) x 37,000 = \( \frac{3,108,000}{100} \) = 31,080
The mayor got 86% of the votes cast which is:
(\( \frac{86}{100} \)) x 31,080 = \( \frac{2,672,880}{100} \) = 26,729 votes.
What is \( 4 \)\( \sqrt{12} \) + \( 2 \)\( \sqrt{3} \)
| 10\( \sqrt{3} \) | |
| 6\( \sqrt{3} \) | |
| 6\( \sqrt{4} \) | |
| 8\( \sqrt{4} \) |
To add these radicals together their radicands must be the same:
4\( \sqrt{12} \) + 2\( \sqrt{3} \)
4\( \sqrt{4 \times 3} \) + 2\( \sqrt{3} \)
4\( \sqrt{2^2 \times 3} \) + 2\( \sqrt{3} \)
(4)(2)\( \sqrt{3} \) + 2\( \sqrt{3} \)
8\( \sqrt{3} \) + 2\( \sqrt{3} \)
Now that the radicands are identical, you can add them together:
8\( \sqrt{3} \) + 2\( \sqrt{3} \)What is the least common multiple of 3 and 9?
| 9 | |
| 8 | |
| 17 | |
| 11 |
The first few multiples of 3 are [3, 6, 9, 12, 15, 18, 21, 24, 27, 30] and the first few multiples of 9 are [9, 18, 27, 36, 45, 54, 63, 72, 81, 90]. The first few multiples they share are [9, 18, 27, 36, 45] making 9 the smallest multiple 3 and 9 have in common.
What is \( \sqrt{\frac{9}{49}} \)?
| \(\frac{3}{7}\) | |
| \(\frac{2}{3}\) | |
| 1 | |
| \(\frac{3}{4}\) |
To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:
\( \sqrt{\frac{9}{49}} \)
\( \frac{\sqrt{9}}{\sqrt{49}} \)
\( \frac{\sqrt{3^2}}{\sqrt{7^2}} \)
\(\frac{3}{7}\)