To raise a term with an exponent to another exponent, retain the base and multiply the exponents:

The amount of flour you need is (1\(\frac{7}{8}\) - 1) cups. Rewrite the quantities so they share a common denominator and subtract:

(\( \frac{15}{8} \) - \( \frac{8}{8} \)) cups
\( \frac{7}{8} \) cups
\(\frac{7}{8}\) cups

The first few multiples of 3 are [3, 6, 9, 12, 15, 18, 21, 24, 27, 30] and the first few multiples of 9 are [9, 18, 27, 36, 45, 54, 63, 72, 81, 90]. The first few multiples they share are [9, 18, 27, 36, 45] making 9 the smallest multiple 3 and 9 have in common.

To multiply terms with radicals, multiply the coefficients and radicands separately:

6\( \sqrt{9} \) x 2\( \sqrt{6} \)
(6 x 2)\( \sqrt{9 \times 6} \)
12\( \sqrt{54} \)

Now we need to simplify the radical:

12\( \sqrt{54} \)
12\( \sqrt{6 \times 9} \)
12\( \sqrt{6 \times 3^2} \)
(12)(3)\( \sqrt{6} \)
36\( \sqrt{6} \)

To add these radicals together their radicands must be the same:

8\( \sqrt{50} \) + 2\( \sqrt{2} \)
8\( \sqrt{25 \times 2} \) + 2\( \sqrt{2} \)
8\( \sqrt{5^2 \times 2} \) + 2\( \sqrt{2} \)
(8)(5)\( \sqrt{2} \) + 2\( \sqrt{2} \)
40\( \sqrt{2} \) + 2\( \sqrt{2} \)

Now that the radicands are identical, you can add them together: