ASVAB Arithmetic Reasoning Practice Test 428900 Results

Your Results Global Average
Questions 5 5
Correct 0 3.15
Score 0% 63%

Review

1

What is \( 8 \)\( \sqrt{48} \) - \( 5 \)\( \sqrt{3} \)

38% Answer Correctly
3\( \sqrt{-7} \)
3\( \sqrt{16} \)
3\( \sqrt{144} \)
27\( \sqrt{3} \)

Solution

To subtract these radicals together their radicands must be the same:

8\( \sqrt{48} \) - 5\( \sqrt{3} \)
8\( \sqrt{16 \times 3} \) - 5\( \sqrt{3} \)
8\( \sqrt{4^2 \times 3} \) - 5\( \sqrt{3} \)
(8)(4)\( \sqrt{3} \) - 5\( \sqrt{3} \)
32\( \sqrt{3} \) - 5\( \sqrt{3} \)

Now that the radicands are identical, you can subtract them:

32\( \sqrt{3} \) - 5\( \sqrt{3} \)
(32 - 5)\( \sqrt{3} \)
27\( \sqrt{3} \)


2

Charlie loaned Roger $200 at an annual interest rate of 2%. If no payments are made, what is the interest owed on this loan at the end of the first year?

74% Answer Correctly
$42
$6
$4
$45

Solution

The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:

interest = annual interest rate x loan amount

i = (\( \frac{6}{100} \)) x $200
i = 0.02 x $200
i = $4


3

What is \( \frac{1}{5} \) x \( \frac{1}{9} \)?

72% Answer Correctly
\(\frac{12}{49}\)
\(\frac{16}{63}\)
\(\frac{1}{45}\)
\(\frac{1}{28}\)

Solution

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{1}{5} \) x \( \frac{1}{9} \) = \( \frac{1 x 1}{5 x 9} \) = \( \frac{1}{45} \) = \(\frac{1}{45}\)


4

A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 40% off." If Roger buys two shirts, each with a regular price of $10, how much will he pay for both shirts?

57% Answer Correctly
$16.00
$4.00
$13.50
$6.00

Solution

By buying two shirts, Roger will save $10 x \( \frac{40}{100} \) = \( \frac{$10 x 40}{100} \) = \( \frac{$400}{100} \) = $4.00 on the second shirt.

So, his total cost will be
$10.00 + ($10.00 - $4.00)
$10.00 + $6.00
$16.00


5

a(b + c) = ab + ac defines which of the following?

74% Answer Correctly

commutative property for division

distributive property for multiplication

commutative property for multiplication

distributive property for division


Solution

The distributive property for multiplication helps in solving expressions like a(b + c). It specifies that the result of multiplying one number by the sum or difference of two numbers can be obtained by multiplying each number individually and then totaling the results: a(b + c) = ab + ac. For example, 4(10-5) = (4 x 10) - (4 x 5) = 40 - 20 = 20.