ASVAB Arithmetic Reasoning Practice Test 430810 Results

Your Results Global Average
Questions 5 5
Correct 0 3.03
Score 0% 61%

Review

1

Which of the following statements about exponents is false?

47% Answer Correctly

b1 = 1

b0 = 1

b1 = b

all of these are false


Solution

A number with an exponent (be) consists of a base (b) raised to a power (e). The exponent indicates the number of times that the base is multiplied by itself. A base with an exponent of 1 equals the base (b1 = b) and a base with an exponent of 0 equals 1 ( (b0 = 1).


2

What is \( \frac{35\sqrt{15}}{5\sqrt{3}} \)?

71% Answer Correctly
7 \( \sqrt{5} \)
\(\frac{1}{7}\) \( \sqrt{\frac{1}{5}} \)
7 \( \sqrt{\frac{1}{5}} \)
\(\frac{1}{5}\) \( \sqrt{\frac{1}{7}} \)

Solution

To divide terms with radicals, divide the coefficients and radicands separately:

\( \frac{35\sqrt{15}}{5\sqrt{3}} \)
\( \frac{35}{5} \) \( \sqrt{\frac{15}{3}} \)
7 \( \sqrt{5} \)


3

9 members of a bridal party need transported to a wedding reception but there are only 2 3-passenger taxis available to take them. How many will need to find other transportation?

75% Answer Correctly
3
4
2
1

Solution

There are 2 3-passenger taxis available so that's 2 x 3 = 6 total seats. There are 9 people needing transportation leaving 9 - 6 = 3 who will have to find other transportation.


4

What is \( \frac{7}{5} \) - \( \frac{4}{7} \)?

61% Answer Correctly
1 \( \frac{6}{35} \)
1 \( \frac{7}{11} \)
2 \( \frac{8}{35} \)
\(\frac{29}{35}\)

Solution

To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 5 are [5, 10, 15, 20, 25, 30, 35, 40, 45, 50] and the first few multiples of 7 are [7, 14, 21, 28, 35, 42, 49, 56, 63, 70]. The first few multiples they share are [35, 70] making 35 the smallest multiple 5 and 7 share.

Next, convert the fractions so each denominator equals the lowest common multiple:

\( \frac{7 x 7}{5 x 7} \) - \( \frac{4 x 5}{7 x 5} \)

\( \frac{49}{35} \) - \( \frac{20}{35} \)

Now, because the fractions share a common denominator, you can subtract them:

\( \frac{49 - 20}{35} \) = \( \frac{29}{35} \) = \(\frac{29}{35}\)


5

How many 1\(\frac{1}{2}\) gallon cans worth of fuel would you need to pour into an empty 6 gallon tank to fill it exactly halfway?

52% Answer Correctly
2
3
5
2

Solution

To fill a 6 gallon tank exactly halfway you'll need 3 gallons of fuel. Each fuel can holds 1\(\frac{1}{2}\) gallons so:

cans = \( \frac{3 \text{ gallons}}{1\frac{1}{2} \text{ gallons}} \) = 2