| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.00 |
| Score | 0% | 60% |
What is \( \frac{4}{7} \) ÷ \( \frac{3}{9} \)?
| \(\frac{1}{56}\) | |
| 1\(\frac{5}{7}\) | |
| \(\frac{3}{40}\) | |
| 12 |
To divide fractions, invert the second fraction and then multiply:
\( \frac{4}{7} \) ÷ \( \frac{3}{9} \) = \( \frac{4}{7} \) x \( \frac{9}{3} \)
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{4}{7} \) x \( \frac{9}{3} \) = \( \frac{4 x 9}{7 x 3} \) = \( \frac{36}{21} \) = 1\(\frac{5}{7}\)
If a mayor is elected with 61% of the votes cast and 63% of a town's 10,000 voters cast a vote, how many votes did the mayor receive?
| 4,725 | |
| 4,158 | |
| 3,843 | |
| 4,347 |
If 63% of the town's 10,000 voters cast ballots the number of votes cast is:
(\( \frac{63}{100} \)) x 10,000 = \( \frac{630,000}{100} \) = 6,300
The mayor got 61% of the votes cast which is:
(\( \frac{61}{100} \)) x 6,300 = \( \frac{384,300}{100} \) = 3,843 votes.
\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?
commutative property for division |
|
commutative property for multiplication |
|
distributive property for division |
|
distributive property for multiplication |
The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).
Solve for \( \frac{4!}{3!} \)
| 72 | |
| \( \frac{1}{30} \) | |
| 4 | |
| \( \frac{1}{72} \) |
A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:
\( \frac{4!}{3!} \)
\( \frac{4 \times 3 \times 2 \times 1}{3 \times 2 \times 1} \)
\( \frac{4}{1} \)
4
The total water usage for a city is 20,000 gallons each day. Of that total, 26% is for personal use and 38% is for industrial use. How many more gallons of water each day is consumed for industrial use over personal use?
| 4,500 | |
| 2,400 | |
| 10,000 | |
| 1,450 |
38% of the water consumption is industrial use and 26% is personal use so (38% - 26%) = 12% more water is used for industrial purposes. 20,000 gallons are consumed daily so industry consumes \( \frac{12}{100} \) x 20,000 gallons = 2,400 gallons.