| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.38 |
| Score | 0% | 68% |
Find the average of the following numbers: 13, 9, 15, 7.
| 13 | |
| 9 | |
| 6 | |
| 11 |
To find the average of these 4 numbers add them together then divide by 4:
\( \frac{13 + 9 + 15 + 7}{4} \) = \( \frac{44}{4} \) = 11
What is \( \frac{49\sqrt{16}}{7\sqrt{4}} \)?
| 7 \( \sqrt{4} \) | |
| 7 \( \sqrt{\frac{1}{4}} \) | |
| \(\frac{1}{7}\) \( \sqrt{4} \) | |
| \(\frac{1}{7}\) \( \sqrt{\frac{1}{4}} \) |
To divide terms with radicals, divide the coefficients and radicands separately:
\( \frac{49\sqrt{16}}{7\sqrt{4}} \)
\( \frac{49}{7} \) \( \sqrt{\frac{16}{4}} \)
7 \( \sqrt{4} \)
Alex loaned Christine $1,400 at an annual interest rate of 6%. If no payments are made, what is the total amount owed at the end of the first year?
| $1,456 | |
| $1,498 | |
| $1,484 | |
| $1,526 |
The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:
interest = annual interest rate x loan amount
i = (\( \frac{6}{100} \)) x $1,400
i = 0.06 x $1,400
No payments were made so the total amount due is the original amount + the accumulated interest:
total = $1,400 + $84What is \( \frac{3}{2} \) + \( \frac{5}{4} \)?
| 1 \( \frac{9}{4} \) | |
| 2\(\frac{3}{4}\) | |
| \( \frac{6}{15} \) | |
| 1 \( \frac{5}{4} \) |
To add these fractions, first find the lowest common multiple of their denominators. The first few multiples of 2 are [2, 4, 6, 8, 10, 12, 14, 16, 18, 20] and the first few multiples of 4 are [4, 8, 12, 16, 20, 24, 28, 32, 36, 40]. The first few multiples they share are [4, 8, 12, 16, 20] making 4 the smallest multiple 2 and 4 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{3 x 2}{2 x 2} \) + \( \frac{5 x 1}{4 x 1} \)
\( \frac{6}{4} \) + \( \frac{5}{4} \)
Now, because the fractions share a common denominator, you can add them:
\( \frac{6 + 5}{4} \) = \( \frac{11}{4} \) = 2\(\frac{3}{4}\)
In a class of 32 students, 12 are taking German and 15 are taking Spanish. Of the students studying German or Spanish, 7 are taking both courses. How many students are not enrolled in either course?
| 27 | |
| 25 | |
| 20 | |
| 12 |
The number of students taking German or Spanish is 12 + 15 = 27. Of that group of 27, 7 are taking both languages so they've been counted twice (once in the German group and once in the Spanish group). Subtracting them out leaves 27 - 7 = 20 who are taking at least one language. 32 - 20 = 12 students who are not taking either language.