The first few multiples of 3 are [3, 6, 9, 12, 15, 18, 21, 24, 27, 30] and the first few multiples of 7 are [7, 14, 21, 28, 35, 42, 49, 56, 63, 70]. The first few multiples they share are [21, 42, 63, 84] making 21 the smallest multiple 3 and 7 have in common.

To add these radicals together their radicands must be the same:

3\( \sqrt{20} \) + 3\( \sqrt{5} \)
3\( \sqrt{4 \times 5} \) + 3\( \sqrt{5} \)
3\( \sqrt{2^2 \times 5} \) + 3\( \sqrt{5} \)
(3)(2)\( \sqrt{5} \) + 3\( \sqrt{5} \)
6\( \sqrt{5} \) + 3\( \sqrt{5} \)

Now that the radicands are identical, you can add them together:

If the tiger has consumed 63 pounds of food in 7 days that's \( \frac{63}{7} \) = 9 pounds of food per day. The tiger needs to consume 126 - 63 = 63 more pounds of food to reach 126 pounds total. At 9 pounds of food per day that's \( \frac{63}{9} \) = 7 more days.

The factors of 20 are [1, 2, 4, 5, 10, 20] and the factors of 76 are [1, 2, 4, 19, 38, 76]. They share 3 factors [1, 2, 4] making 4 the greatest factor 20 and 76 have in common.

The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:

interest = annual interest rate x loan amount

i = (\( \frac{6}{100} \)) x $600
i = 0.02 x $600

No payments were made so the total amount due is the original amount + the accumulated interest: