If the tiger has consumed 60 pounds of food in 4 days that's \( \frac{60}{4} \) = 15 pounds of food per day. The tiger needs to consume 165 - 60 = 105 more pounds of food to reach 165 pounds total. At 15 pounds of food per day that's \( \frac{105}{15} \) = 7 more days.

A factorial has the form n! and is the product of the integer (n) and all the positive integers below it. For example, 5! = 5 x 4 x 3 x 2 x 1 = 120.

The amount of flour you need is (3\(\frac{3}{8}\) - \(\frac{5}{8}\)) cups. Rewrite the quantities so they share a common denominator and subtract:

(\( \frac{27}{8} \) - \( \frac{5}{8} \)) cups
\( \frac{22}{8} \) cups
2\(\frac{3}{4}\) cups

The number of students taking German or Spanish is 12 + 15 = 27. Of that group of 27, 4 are taking both languages so they've been counted twice (once in the German group and once in the Spanish group). Subtracting them out leaves 27 - 4 = 23 who are taking at least one language. 33 - 23 = 10 students who are not taking either language.

To add these fractions, first find the lowest common multiple of their denominators. The first few multiples of 4 are [4, 8, 12, 16, 20, 24, 28, 32, 36, 40] and the first few multiples of 10 are [10, 20, 30, 40, 50, 60, 70, 80, 90]. The first few multiples they share are [20, 40, 60, 80] making 20 the smallest multiple 4 and 10 share.

Next, convert the fractions so each denominator equals the lowest common multiple:

\( \frac{6 x 5}{4 x 5} \) + \( \frac{2 x 2}{10 x 2} \)

\( \frac{30}{20} \) + \( \frac{4}{20} \)

Now, because the fractions share a common denominator, you can add them:

\( \frac{30 + 4}{20} \) = \( \frac{34}{20} \) = 1\(\frac{7}{10}\)