| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.72 |
| Score | 0% | 74% |
How many hours does it take a car to travel 675 miles at an average speed of 75 miles per hour?
| 1 hour | |
| 6 hours | |
| 9 hours | |
| 8 hours |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)Solving for time:
time = \( \frac{\text{distance}}{\text{speed}} \)
time = \( \frac{675mi}{75mph} \)
9 hours
Which of the following is not a prime number?
7 |
|
5 |
|
2 |
|
9 |
A prime number is an integer greater than 1 that has no factors other than 1 and itself. Examples of prime numbers include 2, 3, 5, 7, and 11.
What is \( \frac{9}{6} \) - \( \frac{2}{10} \)?
| \( \frac{9}{15} \) | |
| 1\(\frac{3}{10}\) | |
| \( \frac{5}{12} \) | |
| 1 \( \frac{5}{14} \) |
To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 6 are [6, 12, 18, 24, 30, 36, 42, 48, 54, 60] and the first few multiples of 10 are [10, 20, 30, 40, 50, 60, 70, 80, 90]. The first few multiples they share are [30, 60, 90] making 30 the smallest multiple 6 and 10 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{9 x 5}{6 x 5} \) - \( \frac{2 x 3}{10 x 3} \)
\( \frac{45}{30} \) - \( \frac{6}{30} \)
Now, because the fractions share a common denominator, you can subtract them:
\( \frac{45 - 6}{30} \) = \( \frac{39}{30} \) = 1\(\frac{3}{10}\)
Which of the following is not an integer?
0 |
|
-1 |
|
1 |
|
\({1 \over 2}\) |
An integer is any whole number, including zero. An integer can be either positive or negative. Examples include -77, -1, 0, 55, 119.
What is the distance in miles of a trip that takes 2 hours at an average speed of 45 miles per hour?
| 100 miles | |
| 65 miles | |
| 330 miles | |
| 90 miles |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)Solving for distance:
distance = \( \text{speed} \times \text{time} \)
distance = \( 45mph \times 2h \)
90 miles