ASVAB Arithmetic Reasoning Practice Test 436301 Results

Your Results Global Average
Questions 5 5
Correct 0 2.87
Score 0% 57%

Review

1

\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?

56% Answer Correctly

commutative property for division

distributive property for division

commutative property for multiplication

distributive property for multiplication


Solution

The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).


2

What is \( 9 \)\( \sqrt{18} \) + \( 7 \)\( \sqrt{2} \)

35% Answer Correctly
34\( \sqrt{2} \)
16\( \sqrt{2} \)
16\( \sqrt{18} \)
63\( \sqrt{9} \)

Solution

To add these radicals together their radicands must be the same:

9\( \sqrt{18} \) + 7\( \sqrt{2} \)
9\( \sqrt{9 \times 2} \) + 7\( \sqrt{2} \)
9\( \sqrt{3^2 \times 2} \) + 7\( \sqrt{2} \)
(9)(3)\( \sqrt{2} \) + 7\( \sqrt{2} \)
27\( \sqrt{2} \) + 7\( \sqrt{2} \)

Now that the radicands are identical, you can add them together:

27\( \sqrt{2} \) + 7\( \sqrt{2} \)
(27 + 7)\( \sqrt{2} \)
34\( \sqrt{2} \)


3

What is \( \frac{25\sqrt{35}}{5\sqrt{7}} \)?

71% Answer Correctly
\(\frac{1}{5}\) \( \sqrt{5} \)
5 \( \sqrt{5} \)
5 \( \sqrt{\frac{1}{5}} \)
\(\frac{1}{5}\) \( \sqrt{\frac{1}{5}} \)

Solution

To divide terms with radicals, divide the coefficients and radicands separately:

\( \frac{25\sqrt{35}}{5\sqrt{7}} \)
\( \frac{25}{5} \) \( \sqrt{\frac{35}{7}} \)
5 \( \sqrt{5} \)


4

The __________ is the smallest positive integer that is a multiple of two or more integers.

56% Answer Correctly

absolute value

least common multiple

greatest common factor

least common factor


Solution

The least common multiple (LCM) is the smallest positive integer that is a multiple of two or more integers.


5

What is \( \frac{4}{9} \) ÷ \( \frac{4}{5} \)?

68% Answer Correctly
\(\frac{4}{15}\)
2\(\frac{2}{9}\)
\(\frac{1}{8}\)
\(\frac{5}{9}\)

Solution

To divide fractions, invert the second fraction and then multiply:

\( \frac{4}{9} \) ÷ \( \frac{4}{5} \) = \( \frac{4}{9} \) x \( \frac{5}{4} \)

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{4}{9} \) x \( \frac{5}{4} \) = \( \frac{4 x 5}{9 x 4} \) = \( \frac{20}{36} \) = \(\frac{5}{9}\)