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|---|---|---|
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\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?
commutative property for division |
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distributive property for division |
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commutative property for multiplication |
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distributive property for multiplication |
The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).
What is \( 9 \)\( \sqrt{18} \) + \( 7 \)\( \sqrt{2} \)
| 34\( \sqrt{2} \) | |
| 16\( \sqrt{2} \) | |
| 16\( \sqrt{18} \) | |
| 63\( \sqrt{9} \) |
To add these radicals together their radicands must be the same:
9\( \sqrt{18} \) + 7\( \sqrt{2} \)
9\( \sqrt{9 \times 2} \) + 7\( \sqrt{2} \)
9\( \sqrt{3^2 \times 2} \) + 7\( \sqrt{2} \)
(9)(3)\( \sqrt{2} \) + 7\( \sqrt{2} \)
27\( \sqrt{2} \) + 7\( \sqrt{2} \)
Now that the radicands are identical, you can add them together:
27\( \sqrt{2} \) + 7\( \sqrt{2} \)What is \( \frac{25\sqrt{35}}{5\sqrt{7}} \)?
| \(\frac{1}{5}\) \( \sqrt{5} \) | |
| 5 \( \sqrt{5} \) | |
| 5 \( \sqrt{\frac{1}{5}} \) | |
| \(\frac{1}{5}\) \( \sqrt{\frac{1}{5}} \) |
To divide terms with radicals, divide the coefficients and radicands separately:
\( \frac{25\sqrt{35}}{5\sqrt{7}} \)
\( \frac{25}{5} \) \( \sqrt{\frac{35}{7}} \)
5 \( \sqrt{5} \)
The __________ is the smallest positive integer that is a multiple of two or more integers.
absolute value |
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least common multiple |
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greatest common factor |
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least common factor |
The least common multiple (LCM) is the smallest positive integer that is a multiple of two or more integers.
What is \( \frac{4}{9} \) ÷ \( \frac{4}{5} \)?
| \(\frac{4}{15}\) | |
| 2\(\frac{2}{9}\) | |
| \(\frac{1}{8}\) | |
| \(\frac{5}{9}\) |
To divide fractions, invert the second fraction and then multiply:
\( \frac{4}{9} \) ÷ \( \frac{4}{5} \) = \( \frac{4}{9} \) x \( \frac{5}{4} \)
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{4}{9} \) x \( \frac{5}{4} \) = \( \frac{4 x 5}{9 x 4} \) = \( \frac{20}{36} \) = \(\frac{5}{9}\)