ASVAB Arithmetic Reasoning Practice Test 437374 Results

	Your Results	Global Average
Questions	5	5
Correct	0	3.71
Score	0%	74%

Review

A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 30% off." If Roger buys two shirts, each with a regular price of $43, how much money will he save?

70% Answer Correctly

	$10.75
	$21.50
	$2.15
	$12.90

Solution

By buying two shirts, Roger will save $43 x $ \frac{30}{100} $ = $ \frac{$43 x 30}{100} $ = $ \frac{$1290}{100} $ = $12.90 on the second shirt.

If $ \left|b - 4\right| $ - 7 = 4, which of these is a possible value for b?

62% Answer Correctly

	-5
	-7
	-1
	-9

Solution

First, solve for $ \left|b - 4\right| $:

The value inside the absolute value brackets can be either positive or negative so (b - 4) must equal + 11 or -11 for $ \left|b - 4\right| $ to equal 11:

b - 4 = 11
b = 11 + 4
b = 15

b - 4 = -11
b = -11 + 4
b = -7

So, b = -7 or b = 15.

Which of the following is a mixed number?

82% Answer Correctly

	${a \over 5} $
	${5 \over 7} $
	$1 {2 \over 5} $
	${7 \over 5} $

Solution

A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form ${a \over b}$ where a is the numerator and b is the denominator. An improper fraction (${5 \over 3} $) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number ($1 {2 \over 3} $) which has a whole number part and a fractional part.

What is -6a⁵ + 3a⁵?

66% Answer Correctly

	9a⁵
	-3a⁵
	-9a^-5
	9a^-5

Solution

To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so add the coefficients and retain the base and exponent:

-6a⁵ + 3a⁵
(-6 + 3)a⁵
-3a⁵

What is the next number in this sequence: 1, 5, 9, 13, 17, __________ ?

92% Answer Correctly

	21
	18
	20
	15

Solution

The equation for this sequence is:

a_n = a_n-1 + 4

where n is the term's order in the sequence, a_n is the value of the term, and a_n-1 is the value of the term before a_n. This makes the next number:

a₆ = a₅ + 4
a₆ = 17 + 4
a₆ = 21

	\({a \over 5} \)
	\({5 \over 7} \)
	\(1 {2 \over 5} \)
	\({7 \over 5} \)