| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.34 |
| Score | 0% | 67% |
Convert z-3 to remove the negative exponent.
| \( \frac{3}{z} \) | |
| \( \frac{1}{z^3} \) | |
| \( \frac{1}{z^{-3}} \) | |
| \( \frac{-3}{-z} \) |
To convert a negative exponent to a positive exponent, calculate the positive exponent then take the reciprocal.
What is -b3 x 5b2?
| -5b3 | |
| -5b5 | |
| 4b2 | |
| -5b2 |
To multiply terms with exponents, the base of both exponents must be the same. In this case they are so multiply the coefficients and add the exponents:
-b3 x 5b2
(-1 x 5)b(3 + 2)
-5b5
April scored 77% on her final exam. If each question was worth 3 points and there were 180 possible points on the exam, how many questions did April answer correctly?
| 46 | |
| 57 | |
| 41 | |
| 54 |
April scored 77% on the test meaning she earned 77% of the possible points on the test. There were 180 possible points on the test so she earned 180 x 0.77 = 138 points. Each question is worth 3 points so she got \( \frac{138}{3} \) = 46 questions right.
Find the average of the following numbers: 13, 5, 11, 7.
| 13 | |
| 8 | |
| 9 | |
| 4 |
To find the average of these 4 numbers add them together then divide by 4:
\( \frac{13 + 5 + 11 + 7}{4} \) = \( \frac{36}{4} \) = 9
What is \( \frac{5a^6}{7a^3} \)?
| \(\frac{5}{7}\)a3 | |
| 1\(\frac{2}{5}\)a-3 | |
| \(\frac{5}{7}\)a\(\frac{1}{2}\) | |
| \(\frac{5}{7}\)a2 |
To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:
\( \frac{5a^6}{7a^3} \)
\( \frac{5}{7} \) a(6 - 3)
\(\frac{5}{7}\)a3