ASVAB Arithmetic Reasoning Practice Test 447020 Results

Your Results Global Average
Questions 5 5
Correct 0 3.11
Score 0% 62%

Review

1

Convert 0.0008296 to scientific notation.

62% Answer Correctly
8.296 x 10-3
8.296 x 10-4
0.83 x 10-3
8.296 x 104

Solution

A number in scientific notation has the format 0.000 x 10exponent. To convert to scientific notation, move the decimal point to the right or the left until the number is a decimal between 1 and 10. The exponent of the 10 is the number of places you moved the decimal point and is positive if you moved the decimal point to the left and negative if you moved it to the right:

0.0008296 in scientific notation is 8.296 x 10-4


2

A tiger in a zoo has consumed 35 pounds of food in 5 days. If the tiger continues to eat at the same rate, in how many more days will its total food consumtion be 77 pounds?

56% Answer Correctly
8
10
5
6

Solution

If the tiger has consumed 35 pounds of food in 5 days that's \( \frac{35}{5} \) = 7 pounds of food per day. The tiger needs to consume 77 - 35 = 42 more pounds of food to reach 77 pounds total. At 7 pounds of food per day that's \( \frac{42}{7} \) = 6 more days.


3

What is \( \frac{10\sqrt{45}}{5\sqrt{9}} \)?

71% Answer Correctly
5 \( \sqrt{\frac{1}{2}} \)
\(\frac{1}{5}\) \( \sqrt{2} \)
2 \( \sqrt{5} \)
\(\frac{1}{2}\) \( \sqrt{\frac{1}{5}} \)

Solution

To divide terms with radicals, divide the coefficients and radicands separately:

\( \frac{10\sqrt{45}}{5\sqrt{9}} \)
\( \frac{10}{5} \) \( \sqrt{\frac{45}{9}} \)
2 \( \sqrt{5} \)


4

What is -2a3 x 6a5?

75% Answer Correctly
-12a2
-12a8
4a15
-12a-2

Solution

To multiply terms with exponents, the base of both exponents must be the same. In this case they are so multiply the coefficients and add the exponents:

-2a3 x 6a5
(-2 x 6)a(3 + 5)
-12a8


5

If a rectangle is twice as long as it is wide and has a perimeter of 30 meters, what is the area of the rectangle?

47% Answer Correctly
98 m2
50 m2
2 m2
128 m2

Solution

The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 30 meters so the equation becomes: 2w + 2h = 30.

Putting these two equations together and solving for width (w):

2w + 2h = 30
w + h = \( \frac{30}{2} \)
w + h = 15
w = 15 - h

From the question we know that h = 2w so substituting 2w for h gives us:

w = 15 - 2w
3w = 15
w = \( \frac{15}{3} \)
w = 5

Since h = 2w that makes h = (2 x 5) = 10 and the area = h x w = 5 x 10 = 50 m2