Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):

2 + (4 + 3) ÷ 2 x 3 - 4²
P: 2 + (7) ÷ 2 x 3 - 4²
E: 2 + 7 ÷ 2 x 3 - 16
MD: 2 + \( \frac{7}{2} \) x 3 - 16
MD: 2 + \( \frac{21}{2} \) - 16
AS: \( \frac{4}{2} \) + \( \frac{21}{2} \) - 16
AS: \( \frac{25}{2} \) - 16
AS: \( \frac{25 - 32}{2} \)
\( \frac{-7}{2} \)
-3\(\frac{1}{2}\)

If 47% of the town's 32,000 voters cast ballots the number of votes cast is:

(\( \frac{47}{100} \)) x 32,000 = \( \frac{1,504,000}{100} \) = 15,040

The mayor got 64% of the votes cast which is:

(\( \frac{64}{100} \)) x 15,040 = \( \frac{962,560}{100} \) = 9,626 votes.

To simplify this fraction, first find the greatest common factor between them. The factors of 28 are [1, 2, 4, 7, 14, 28] and the factors of 52 are [1, 2, 4, 13, 26, 52]. They share 3 factors [1, 2, 4] making 4 their greatest common factor (GCF).

Next, divide both numerator and denominator by the GCF:

\( \frac{28}{52} \) = \( \frac{\frac{28}{4}}{\frac{52}{4}} \) = \( \frac{7}{13} \)

In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 4 workers at the company now and that's enough to staff 2 crews so there are \( \frac{4}{2} \) = 2 workers on a crew. 6 crews are needed for the busy season which, at 2 workers per crew, means that the roofing company will need 6 x 2 = 12 total workers to staff the crews during the busy season. The company already employs 4 workers so they need to add 12 - 4 = 8 new staff for the busy season.

A factor is a positive integer that divides evenly into a given number. For example, the factors of 8 are 1, 2, 4, and 8.