The equation for this sequence is:

a_n = a_n-1 + 9

where n is the term's order in the sequence, a_n is the value of the term, and a_n-1 is the value of the term before a_n. This makes the next number:

a₆ = a₅ + 9
a₆ = 37 + 9
a₆ = 46

The distributive property for multiplication helps in solving expressions like a(b + c). It specifies that the result of multiplying one number by the sum or difference of two numbers can be obtained by multiplying each number individually and then totaling the results: a(b + c) = ab + ac. For example, 4(10-5) = (4 x 10) - (4 x 5) = 40 - 20 = 20.

In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 15 workers at the company now and that's enough to staff 5 crews so there are \( \frac{15}{5} \) = 3 workers on a crew. 8 crews are needed for the busy season which, at 3 workers per crew, means that the roofing company will need 8 x 3 = 24 total workers to staff the crews during the busy season. The company already employs 15 workers so they need to add 24 - 15 = 9 new staff for the busy season.

Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):

4 + (4 + 3) ÷ 4 x 3 - 2²
P: 4 + (7) ÷ 4 x 3 - 2²
E: 4 + 7 ÷ 4 x 3 - 4
MD: 4 + \( \frac{7}{4} \) x 3 - 4
MD: 4 + \( \frac{21}{4} \) - 4
AS: \( \frac{16}{4} \) + \( \frac{21}{4} \) - 4
AS: \( \frac{37}{4} \) - 4
AS: \( \frac{37 - 16}{4} \)
\( \frac{21}{4} \)
5\(\frac{1}{4}\)

Average speed in miles per hour is the number of miles traveled divided by the number of hours:

Solving for time:

time = \( \frac{\text{distance}}{\text{speed}} \)
time = \( \frac{300mi}{75mph} \)
4 hours