| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.71 |
| Score | 0% | 54% |
If there were a total of 100 raffle tickets sold and you bought 7 tickets, what's the probability that you'll win the raffle?
| 10% | |
| 1% | |
| 7% | |
| 8% |
You have 7 out of the total of 100 raffle tickets sold so you have a (\( \frac{7}{100} \)) x 100 = \( \frac{7 \times 100}{100} \) = \( \frac{700}{100} \) = 7% chance to win the raffle.
What is \( 3 \)\( \sqrt{80} \) + \( 3 \)\( \sqrt{5} \)
| 9\( \sqrt{5} \) | |
| 15\( \sqrt{5} \) | |
| 9\( \sqrt{400} \) | |
| 9\( \sqrt{16} \) |
To add these radicals together their radicands must be the same:
3\( \sqrt{80} \) + 3\( \sqrt{5} \)
3\( \sqrt{16 \times 5} \) + 3\( \sqrt{5} \)
3\( \sqrt{4^2 \times 5} \) + 3\( \sqrt{5} \)
(3)(4)\( \sqrt{5} \) + 3\( \sqrt{5} \)
12\( \sqrt{5} \) + 3\( \sqrt{5} \)
Now that the radicands are identical, you can add them together:
12\( \sqrt{5} \) + 3\( \sqrt{5} \)Convert y-3 to remove the negative exponent.
| \( \frac{1}{y^3} \) | |
| \( \frac{-1}{-3y} \) | |
| \( \frac{1}{y^{-3}} \) | |
| \( \frac{-3}{-y} \) |
To convert a negative exponent to a positive exponent, calculate the positive exponent then take the reciprocal.
A sports card collection contains football, baseball, and basketball cards. If the ratio of football to baseball cards is 7 to 2 and the ratio of baseball to basketball cards is 7 to 1, what is the ratio of football to basketball cards?
| 49:2 | |
| 9:6 | |
| 3:2 | |
| 7:1 |
The ratio of football cards to baseball cards is 7:2 and the ratio of baseball cards to basketball cards is 7:1. To solve this problem, we need the baseball card side of each ratio to be equal so we need to rewrite the ratios in terms of a common number of baseball cards. (Think of this like finding the common denominator when adding fractions.) The ratio of football to baseball cards can also be written as 49:14 and the ratio of baseball cards to basketball cards as 14:2. So, the ratio of football cards to basketball cards is football:baseball, baseball:basketball or 49:14, 14:2 which reduces to 49:2.
If all of a roofing company's 4 workers are required to staff 2 roofing crews, how many workers need to be added during the busy season in order to send 7 complete crews out on jobs?
| 10 | |
| 19 | |
| 7 | |
| 4 |
In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 4 workers at the company now and that's enough to staff 2 crews so there are \( \frac{4}{2} \) = 2 workers on a crew. 7 crews are needed for the busy season which, at 2 workers per crew, means that the roofing company will need 7 x 2 = 14 total workers to staff the crews during the busy season. The company already employs 4 workers so they need to add 14 - 4 = 10 new staff for the busy season.