ASVAB Arithmetic Reasoning Practice Test 452103 Results

Your Results Global Average
Questions 5 5
Correct 0 3.36
Score 0% 67%

Review

1

What is the distance in miles of a trip that takes 3 hours at an average speed of 60 miles per hour?

87% Answer Correctly
375 miles
180 miles
275 miles
200 miles

Solution

Average speed in miles per hour is the number of miles traveled divided by the number of hours:

speed = \( \frac{\text{distance}}{\text{time}} \)

Solving for distance:

distance = \( \text{speed} \times \text{time} \)
distance = \( 60mph \times 3h \)
180 miles


2

A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 25% off." If Ezra buys two shirts, each with a regular price of $18, how much will he pay for both shirts?

57% Answer Correctly
$31.50
$13.50
$26.10
$4.50

Solution

By buying two shirts, Ezra will save $18 x \( \frac{25}{100} \) = \( \frac{$18 x 25}{100} \) = \( \frac{$450}{100} \) = $4.50 on the second shirt.

So, his total cost will be
$18.00 + ($18.00 - $4.50)
$18.00 + $13.50
$31.50


3

What is 4\( \sqrt{8} \) x 3\( \sqrt{2} \)?

41% Answer Correctly
7\( \sqrt{16} \)
7\( \sqrt{8} \)
48
12\( \sqrt{10} \)

Solution

To multiply terms with radicals, multiply the coefficients and radicands separately:

4\( \sqrt{8} \) x 3\( \sqrt{2} \)
(4 x 3)\( \sqrt{8 \times 2} \)
12\( \sqrt{16} \)

Now we need to simplify the radical:

12\( \sqrt{16} \)
12\( \sqrt{4^2} \)
(12)(4)
48


4

How many hours does it take a car to travel 180 miles at an average speed of 20 miles per hour?

86% Answer Correctly
2 hours
9 hours
3 hours
8 hours

Solution

Average speed in miles per hour is the number of miles traveled divided by the number of hours:

speed = \( \frac{\text{distance}}{\text{time}} \)

Solving for time:

time = \( \frac{\text{distance}}{\text{speed}} \)
time = \( \frac{180mi}{20mph} \)
9 hours


5

Convert c-5 to remove the negative exponent.

68% Answer Correctly
\( \frac{-5}{c} \)
\( \frac{1}{c^5} \)
\( \frac{-1}{-5c} \)
\( \frac{-1}{c^{-5}} \)

Solution

To convert a negative exponent to a positive exponent, calculate the positive exponent then take the reciprocal.