To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 2 are [2, 4, 6, 8, 10, 12, 14, 16, 18, 20] and the first few multiples of 4 are [4, 8, 12, 16, 20, 24, 28, 32, 36, 40]. The first few multiples they share are [4, 8, 12, 16, 20] making 4 the smallest multiple 2 and 4 share.

Next, convert the fractions so each denominator equals the lowest common multiple:

\( \frac{5 x 2}{2 x 2} \) - \( \frac{8 x 1}{4 x 1} \)

\( \frac{10}{4} \) - \( \frac{8}{4} \)

Now, because the fractions share a common denominator, you can subtract them:

\( \frac{10 - 8}{4} \) = \( \frac{2}{4} \) = \(\frac{1}{2}\)

A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:

\( \frac{6!}{5!} \)
\( \frac{6 \times 5 \times 4 \times 3 \times 2 \times 1}{5 \times 4 \times 3 \times 2 \times 1} \)
\( \frac{6}{1} \)
6

Monica scored 86% on the test meaning she earned 86% of the possible points on the test. There were 360 possible points on the test so she earned 360 x 0.86 = 308 points. Each question is worth 4 points so she got \( \frac{308}{4} \) = 77 questions right.

The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:

interest = annual interest rate x loan amount

i = (\( \frac{6}{100} \)) x $1,200
i = 0.05 x $1,200

No payments were made so the total amount due is the original amount + the accumulated interest:

The amount of flour you need is (2\(\frac{5}{8}\) - 1\(\frac{3}{8}\)) cups. Rewrite the quantities so they share a common denominator and subtract:

(\( \frac{21}{8} \) - \( \frac{11}{8} \)) cups
\( \frac{10}{8} \) cups
1\(\frac{1}{4}\) cups