| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.64 |
| Score | 0% | 53% |
Solve for \( \frac{4!}{5!} \)
| 72 | |
| \( \frac{1}{5} \) | |
| 120 | |
| \( \frac{1}{60480} \) |
A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:
\( \frac{4!}{5!} \)
\( \frac{4 \times 3 \times 2 \times 1}{5 \times 4 \times 3 \times 2 \times 1} \)
\( \frac{1}{5} \)
\( \frac{1}{5} \)
A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 50% off." If Frank buys two shirts, each with a regular price of $45, how much will he pay for both shirts?
| $56.25 | |
| $22.50 | |
| $67.50 | |
| $58.50 |
By buying two shirts, Frank will save $45 x \( \frac{50}{100} \) = \( \frac{$45 x 50}{100} \) = \( \frac{$2250}{100} \) = $22.50 on the second shirt.
So, his total cost will be
$45.00 + ($45.00 - $22.50)
$45.00 + $22.50
$67.50
What is \( 8 \)\( \sqrt{48} \) + \( 9 \)\( \sqrt{3} \)
| 17\( \sqrt{3} \) | |
| 72\( \sqrt{3} \) | |
| 41\( \sqrt{3} \) | |
| 72\( \sqrt{144} \) |
To add these radicals together their radicands must be the same:
8\( \sqrt{48} \) + 9\( \sqrt{3} \)
8\( \sqrt{16 \times 3} \) + 9\( \sqrt{3} \)
8\( \sqrt{4^2 \times 3} \) + 9\( \sqrt{3} \)
(8)(4)\( \sqrt{3} \) + 9\( \sqrt{3} \)
32\( \sqrt{3} \) + 9\( \sqrt{3} \)
Now that the radicands are identical, you can add them together:
32\( \sqrt{3} \) + 9\( \sqrt{3} \)On average, the center for a basketball team hits 30% of his shots while a guard on the same team hits 35% of his shots. If the guard takes 30 shots during a game, how many shots will the center have to take to score as many points as the guard assuming each shot is worth the same number of points?
| 19 | |
| 30 | |
| 18 | |
| 33 |
guard shots made = shots taken x \( \frac{\text{% made}}{100} \) = 30 x \( \frac{35}{100} \) = \( \frac{35 x 30}{100} \) = \( \frac{1050}{100} \) = 10 shots
The center makes 30% of his shots so he'll have to take:
shots made = shots taken x \( \frac{\text{% made}}{100} \)
shots taken = \( \frac{\text{shots taken}}{\frac{\text{% made}}{100}} \)
to make as many shots as the guard. Plugging in values for the center gives us:
center shots taken = \( \frac{10}{\frac{30}{100}} \) = 10 x \( \frac{100}{30} \) = \( \frac{10 x 100}{30} \) = \( \frac{1000}{30} \) = 33 shots
to make the same number of shots as the guard and thus score the same number of points.
A bread recipe calls for 2 cups of flour. If you only have 1\(\frac{3}{4}\) cups, how much more flour is needed?
| 2\(\frac{5}{8}\) cups | |
| \(\frac{3}{4}\) cups | |
| \(\frac{1}{4}\) cups | |
| 1\(\frac{3}{4}\) cups |
The amount of flour you need is (2 - 1\(\frac{3}{4}\)) cups. Rewrite the quantities so they share a common denominator and subtract:
(\( \frac{16}{8} \) - \( \frac{14}{8} \)) cups
\( \frac{2}{8} \) cups
\(\frac{1}{4}\) cups