| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.37 |
| Score | 0% | 67% |
What is (c2)4?
| c6 | |
| c2 | |
| c8 | |
| 2c4 |
To raise a term with an exponent to another exponent, retain the base and multiply the exponents:
(c2)4Damon loaned Bob $1,400 at an annual interest rate of 4%. If no payments are made, what is the interest owed on this loan at the end of the first year?
| $28 | |
| $12 | |
| $56 | |
| $22 |
The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:
interest = annual interest rate x loan amount
i = (\( \frac{6}{100} \)) x $1,400
i = 0.04 x $1,400
i = $56
What is 6a6 - 8a6?
| -2a6 | |
| 2a-6 | |
| 2a6 | |
| 14a12 |
To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so subtract the coefficients and retain the base and exponent:
6a6 - 8a6
(6 - 8)a6
-2a6
Find the average of the following numbers: 14, 8, 14, 8.
| 9 | |
| 8 | |
| 11 | |
| 13 |
To find the average of these 4 numbers add them together then divide by 4:
\( \frac{14 + 8 + 14 + 8}{4} \) = \( \frac{44}{4} \) = 11
What is \( 3 \)\( \sqrt{75} \) - \( 4 \)\( \sqrt{3} \)
| 12\( \sqrt{75} \) | |
| -1\( \sqrt{225} \) | |
| 12\( \sqrt{3} \) | |
| 11\( \sqrt{3} \) |
To subtract these radicals together their radicands must be the same:
3\( \sqrt{75} \) - 4\( \sqrt{3} \)
3\( \sqrt{25 \times 3} \) - 4\( \sqrt{3} \)
3\( \sqrt{5^2 \times 3} \) - 4\( \sqrt{3} \)
(3)(5)\( \sqrt{3} \) - 4\( \sqrt{3} \)
15\( \sqrt{3} \) - 4\( \sqrt{3} \)
Now that the radicands are identical, you can subtract them:
15\( \sqrt{3} \) - 4\( \sqrt{3} \)