| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.53 |
| Score | 0% | 71% |
What is the distance in miles of a trip that takes 6 hours at an average speed of 50 miles per hour?
| 200 miles | |
| 420 miles | |
| 240 miles | |
| 300 miles |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)Solving for distance:
distance = \( \text{speed} \times \text{time} \)
distance = \( 50mph \times 6h \)
300 miles
A tiger in a zoo has consumed 55 pounds of food in 5 days. If the tiger continues to eat at the same rate, in how many more days will its total food consumtion be 132 pounds?
| 6 | |
| 8 | |
| 4 | |
| 7 |
If the tiger has consumed 55 pounds of food in 5 days that's \( \frac{55}{5} \) = 11 pounds of food per day. The tiger needs to consume 132 - 55 = 77 more pounds of food to reach 132 pounds total. At 11 pounds of food per day that's \( \frac{77}{11} \) = 7 more days.
What is -4b3 + 3b3?
| 7b3 | |
| 7b-3 | |
| -7b-3 | |
| -b3 |
To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so add the coefficients and retain the base and exponent:
-4b3 + 3b3
(-4 + 3)b3
-b3
Solve for \( \frac{2!}{6!} \)
| \( \frac{1}{60480} \) | |
| \( \frac{1}{42} \) | |
| \( \frac{1}{360} \) | |
| 4 |
A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:
\( \frac{2!}{6!} \)
\( \frac{2 \times 1}{6 \times 5 \times 4 \times 3 \times 2 \times 1} \)
\( \frac{1}{6 \times 5 \times 4 \times 3} \)
\( \frac{1}{360} \)
What is the greatest common factor of 16 and 80?
| 12 | |
| 7 | |
| 16 | |
| 1 |
The factors of 16 are [1, 2, 4, 8, 16] and the factors of 80 are [1, 2, 4, 5, 8, 10, 16, 20, 40, 80]. They share 5 factors [1, 2, 4, 8, 16] making 16 the greatest factor 16 and 80 have in common.