| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.24 |
| Score | 0% | 65% |
A triathlon course includes a 500m swim, a 20.8km bike ride, and a 9.1km run. What is the total length of the race course?
| 29.6km | |
| 35.3km | |
| 30.4km | |
| 58.7km |
To add these distances, they must share the same unit so first you need to first convert the swim distance from meters (m) to kilometers (km) before adding it to the bike and run distances which are already in km. To convert 500 meters to kilometers, divide the distance by 1000 to get 0.5km then add the remaining distances:
total distance = swim + bike + run
total distance = 0.5km + 20.8km + 9.1km
total distance = 30.4km
On average, the center for a basketball team hits 30% of his shots while a guard on the same team hits 45% of his shots. If the guard takes 15 shots during a game, how many shots will the center have to take to score as many points as the guard assuming each shot is worth the same number of points?
| 12 | |
| 20 | |
| 10 | |
| 18 |
guard shots made = shots taken x \( \frac{\text{% made}}{100} \) = 15 x \( \frac{45}{100} \) = \( \frac{45 x 15}{100} \) = \( \frac{675}{100} \) = 6 shots
The center makes 30% of his shots so he'll have to take:
shots made = shots taken x \( \frac{\text{% made}}{100} \)
shots taken = \( \frac{\text{shots taken}}{\frac{\text{% made}}{100}} \)
to make as many shots as the guard. Plugging in values for the center gives us:
center shots taken = \( \frac{6}{\frac{30}{100}} \) = 6 x \( \frac{100}{30} \) = \( \frac{6 x 100}{30} \) = \( \frac{600}{30} \) = 20 shots
to make the same number of shots as the guard and thus score the same number of points.
Cooks are needed to prepare for a large party. Each cook can bake either 3 large cakes or 20 small cakes per hour. The kitchen is available for 2 hours and 33 large cakes and 160 small cakes need to be baked.
How many cooks are required to bake the required number of cakes during the time the kitchen is available?
| 10 | |
| 12 | |
| 7 | |
| 9 |
If a single cook can bake 3 large cakes per hour and the kitchen is available for 2 hours, a single cook can bake 3 x 2 = 6 large cakes during that time. 33 large cakes are needed for the party so \( \frac{33}{6} \) = 5\(\frac{1}{2}\) cooks are needed to bake the required number of large cakes.
If a single cook can bake 20 small cakes per hour and the kitchen is available for 2 hours, a single cook can bake 20 x 2 = 40 small cakes during that time. 160 small cakes are needed for the party so \( \frac{160}{40} \) = 4 cooks are needed to bake the required number of small cakes.
Because you can't employ a fractional cook, round the number of cooks needed for each type of cake up to the next whole number resulting in 6 + 4 = 10 cooks.
If a car travels 405 miles in 9 hours, what is the average speed?
| 75 mph | |
| 45 mph | |
| 70 mph | |
| 40 mph |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)4! = ?
3 x 2 x 1 |
|
4 x 3 x 2 x 1 |
|
5 x 4 x 3 x 2 x 1 |
|
4 x 3 |
A factorial has the form n! and is the product of the integer (n) and all the positive integers below it. For example, 5! = 5 x 4 x 3 x 2 x 1 = 120.