| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.93 |
| Score | 0% | 59% |
A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 30% off." If Charlie buys two shirts, each with a regular price of $19, how much will he pay for both shirts?
| $19.95 | |
| $13.30 | |
| $32.30 | |
| $22.80 |
By buying two shirts, Charlie will save $19 x \( \frac{30}{100} \) = \( \frac{$19 x 30}{100} \) = \( \frac{$570}{100} \) = $5.70 on the second shirt.
So, his total cost will be
$19.00 + ($19.00 - $5.70)
$19.00 + $13.30
$32.30
Bob loaned Roger $200 at an annual interest rate of 7%. If no payments are made, what is the interest owed on this loan at the end of the first year?
| $14 | |
| $13 | |
| $30 | |
| $24 |
The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:
interest = annual interest rate x loan amount
i = (\( \frac{6}{100} \)) x $200
i = 0.07 x $200
i = $14
A machine in a factory has an error rate of 3 parts per 100. The machine normally runs 24 hours a day and produces 9 parts per hour. Yesterday the machine was shut down for 3 hours for maintenance.
How many error-free parts did the machine produce yesterday?
| 183.3 | |
| 131 | |
| 108.3 | |
| 157.9 |
The hourly error rate for this machine is the error rate in parts per 100 multiplied by the number of parts produced per hour:
\( \frac{3}{100} \) x 9 = \( \frac{3 \times 9}{100} \) = \( \frac{27}{100} \) = 0.27 errors per hour
So, in an average hour, the machine will produce 9 - 0.27 = 8.73 error free parts.
The machine ran for 24 - 3 = 21 hours yesterday so you would expect that 21 x 8.73 = 183.3 error free parts were produced yesterday.
Solve for \( \frac{5!}{6!} \)
| \( \frac{1}{6} \) | |
| 3024 | |
| 8 | |
| 6720 |
A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:
\( \frac{5!}{6!} \)
\( \frac{5 \times 4 \times 3 \times 2 \times 1}{6 \times 5 \times 4 \times 3 \times 2 \times 1} \)
\( \frac{1}{6} \)
\( \frac{1}{6} \)
If a rectangle is twice as long as it is wide and has a perimeter of 42 meters, what is the area of the rectangle?
| 162 m2 | |
| 72 m2 | |
| 18 m2 | |
| 98 m2 |
The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 42 meters so the equation becomes: 2w + 2h = 42.
Putting these two equations together and solving for width (w):
2w + 2h = 42
w + h = \( \frac{42}{2} \)
w + h = 21
w = 21 - h
From the question we know that h = 2w so substituting 2w for h gives us:
w = 21 - 2w
3w = 21
w = \( \frac{21}{3} \)
w = 7
Since h = 2w that makes h = (2 x 7) = 14 and the area = h x w = 7 x 14 = 98 m2