| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.53 |
| Score | 0% | 71% |
A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 40% off." If Alex buys two shirts, each with a regular price of $15, how much money will he save?
| $6.00 | |
| $4.50 | |
| $3.00 | |
| $1.50 |
By buying two shirts, Alex will save $15 x \( \frac{40}{100} \) = \( \frac{$15 x 40}{100} \) = \( \frac{$600}{100} \) = $6.00 on the second shirt.
Frank loaned Ezra $500 at an annual interest rate of 1%. If no payments are made, what is the interest owed on this loan at the end of the first year?
| $26 | |
| $36 | |
| $5 | |
| $12 |
The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:
interest = annual interest rate x loan amount
i = (\( \frac{6}{100} \)) x $500
i = 0.01 x $500
i = $5
Simplify \( \frac{20}{80} \).
| \( \frac{10}{13} \) | |
| \( \frac{4}{9} \) | |
| \( \frac{4}{19} \) | |
| \( \frac{1}{4} \) |
To simplify this fraction, first find the greatest common factor between them. The factors of 20 are [1, 2, 4, 5, 10, 20] and the factors of 80 are [1, 2, 4, 5, 8, 10, 16, 20, 40, 80]. They share 6 factors [1, 2, 4, 5, 10, 20] making 20 their greatest common factor (GCF).
Next, divide both numerator and denominator by the GCF:
\( \frac{20}{80} \) = \( \frac{\frac{20}{20}}{\frac{80}{20}} \) = \( \frac{1}{4} \)
\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?
distributive property for multiplication |
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distributive property for division |
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commutative property for division |
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commutative property for multiplication |
The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).
14 members of a bridal party need transported to a wedding reception but there are only 4 3-passenger taxis available to take them. How many will need to find other transportation?
| 6 | |
| 3 | |
| 8 | |
| 2 |
There are 4 3-passenger taxis available so that's 4 x 3 = 12 total seats. There are 14 people needing transportation leaving 14 - 12 = 2 who will have to find other transportation.