| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.49 |
| Score | 0% | 70% |
Solve for \( \frac{4!}{5!} \)
| \( \frac{1}{9} \) | |
| 72 | |
| \( \frac{1}{5} \) | |
| \( \frac{1}{42} \) |
A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:
\( \frac{4!}{5!} \)
\( \frac{4 \times 3 \times 2 \times 1}{5 \times 4 \times 3 \times 2 \times 1} \)
\( \frac{1}{5} \)
\( \frac{1}{5} \)
What is \( \sqrt{\frac{16}{9}} \)?
| 1\(\frac{3}{4}\) | |
| 2\(\frac{2}{3}\) | |
| 1 | |
| 1\(\frac{1}{3}\) |
To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:
\( \sqrt{\frac{16}{9}} \)
\( \frac{\sqrt{16}}{\sqrt{9}} \)
\( \frac{\sqrt{4^2}}{\sqrt{3^2}} \)
\( \frac{4}{3} \)
1\(\frac{1}{3}\)
8 members of a bridal party need transported to a wedding reception but there are only 2 3-passenger taxis available to take them. How many will need to find other transportation?
| 6 | |
| 2 | |
| 4 | |
| 5 |
There are 2 3-passenger taxis available so that's 2 x 3 = 6 total seats. There are 8 people needing transportation leaving 8 - 6 = 2 who will have to find other transportation.
A triathlon course includes a 400m swim, a 30.3km bike ride, and a 5.7km run. What is the total length of the race course?
| 34.1km | |
| 39.7km | |
| 42.4km | |
| 36.4km |
To add these distances, they must share the same unit so first you need to first convert the swim distance from meters (m) to kilometers (km) before adding it to the bike and run distances which are already in km. To convert 400 meters to kilometers, divide the distance by 1000 to get 0.4km then add the remaining distances:
total distance = swim + bike + run
total distance = 0.4km + 30.3km + 5.7km
total distance = 36.4km
What is the next number in this sequence: 1, 5, 13, 25, 41, __________ ?
| 61 | |
| 59 | |
| 63 | |
| 60 |
The equation for this sequence is:
an = an-1 + 4(n - 1)
where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:
a6 = a5 + 4(6 - 1)
a6 = 41 + 4(5)
a6 = 61