To subtract these radicals together their radicands must be the same:

5\( \sqrt{28} \) - 9\( \sqrt{7} \)
5\( \sqrt{4 \times 7} \) - 9\( \sqrt{7} \)
5\( \sqrt{2^2 \times 7} \) - 9\( \sqrt{7} \)
(5)(2)\( \sqrt{7} \) - 9\( \sqrt{7} \)
10\( \sqrt{7} \) - 9\( \sqrt{7} \)

Now that the radicands are identical, you can subtract them:

To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:

\( \frac{5c^6}{7c^4} \)
\( \frac{5}{7} \) c^{(6 - 4)}
\(\frac{5}{7}\)c²

By buying two shirts, Ezra will save $29 x \( \frac{50}{100} \) = \( \frac{$29 x 50}{100} \) = \( \frac{$1450}{100} \) = $14.50 on the second shirt.

So, his total cost will be
$29.00 + ($29.00 - $14.50)
$29.00 + $14.50
$43.50

A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:

\( \frac{3!}{4!} \)
\( \frac{3 \times 2 \times 1}{4 \times 3 \times 2 \times 1} \)
\( \frac{1}{4} \)
\( \frac{1}{4} \)

The ratio of football cards to baseball cards is 3:2 and the ratio of baseball cards to basketball cards is 3:1. To solve this problem, we need the baseball card side of each ratio to be equal so we need to rewrite the ratios in terms of a common number of baseball cards. (Think of this like finding the common denominator when adding fractions.) The ratio of football to baseball cards can also be written as 9:6 and the ratio of baseball cards to basketball cards as 6:2. So, the ratio of football cards to basketball cards is football:baseball, baseball:basketball or 9:6, 6:2 which reduces to 9:2.