ASVAB Arithmetic Reasoning Practice Test 471983 Results

Your Results Global Average
Questions 5 5
Correct 0 3.45
Score 0% 69%

Review

1

Which of the following is a mixed number?

83% Answer Correctly

\(1 {2 \over 5} \)

\({7 \over 5} \)

\({5 \over 7} \)

\({a \over 5} \)


Solution

A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.


2

What is 4y3 + 3y3?

66% Answer Correctly
7y3
7y-6
7y6
-y-3

Solution

To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so add the coefficients and retain the base and exponent:

4y3 + 3y3
(4 + 3)y3
7y3


3

The __________ is the greatest factor that divides two integers.

67% Answer Correctly

greatest common factor

absolute value

greatest common multiple

least common multiple


Solution

The greatest common factor (GCF) is the greatest factor that divides two integers.


4

If \(\left|a\right| = 7\), which of the following best describes a?

67% Answer Correctly

none of these is correct

a = 7

a = 7 or a = -7

a = -7


Solution

The absolute value is the positive magnitude of a particular number or variable and is indicated by two vertical lines: \(\left|-5\right| = 5\). In the case of a variable absolute value (\(\left|a\right| = 5\)) the value of a can be either positive or negative (a = -5 or a = 5).


5

What is \( \frac{-7b^8}{9b^2} \)?

60% Answer Correctly
-\(\frac{7}{9}\)b6
-\(\frac{7}{9}\)b-6
-\(\frac{7}{9}\)b\(\frac{1}{4}\)
-\(\frac{7}{9}\)b4

Solution

To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:

\( \frac{-7b^8}{9b^2} \)
\( \frac{-7}{9} \) b(8 - 2)
-\(\frac{7}{9}\)b6