| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.26 |
| Score | 0% | 65% |
What is \( \sqrt{\frac{36}{36}} \)?
| 1\(\frac{4}{5}\) | |
| 3 | |
| 1 | |
| \(\frac{2}{3}\) |
To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:
\( \sqrt{\frac{36}{36}} \)
\( \frac{\sqrt{36}}{\sqrt{36}} \)
\( \frac{\sqrt{6^2}}{\sqrt{6^2}} \)
1
What is \( \frac{3}{6} \) ÷ \( \frac{4}{9} \)?
| 1\(\frac{1}{8}\) | |
| \(\frac{2}{15}\) | |
| \(\frac{8}{35}\) | |
| 6\(\frac{3}{4}\) |
To divide fractions, invert the second fraction and then multiply:
\( \frac{3}{6} \) ÷ \( \frac{4}{9} \) = \( \frac{3}{6} \) x \( \frac{9}{4} \)
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{3}{6} \) x \( \frac{9}{4} \) = \( \frac{3 x 9}{6 x 4} \) = \( \frac{27}{24} \) = 1\(\frac{1}{8}\)
If \( \left|y + 9\right| \) + 9 = -2, which of these is a possible value for y?
| -6 | |
| 3 | |
| -9 | |
| 2 |
First, solve for \( \left|y + 9\right| \):
\( \left|y + 9\right| \) + 9 = -2
\( \left|y + 9\right| \) = -2 - 9
\( \left|y + 9\right| \) = -11
The value inside the absolute value brackets can be either positive or negative so (y + 9) must equal - 11 or --11 for \( \left|y + 9\right| \) to equal -11:
| y + 9 = -11 y = -11 - 9 y = -20 | y + 9 = 11 y = 11 - 9 y = 2 |
So, y = 2 or y = -20.
This property states taht the order of addition or multiplication does not mater. For example, 2 + 5 and 5 + 2 are equivalent.
commutative |
|
PEDMAS |
|
associative |
|
distributive |
The commutative property states that, when adding or multiplying numbers, the order in which they're added or multiplied does not matter. For example, 3 + 4 and 4 + 3 give the same result, as do 3 x 4 and 4 x 3.
If \(\left|a\right| = 7\), which of the following best describes a?
a = 7 |
|
none of these is correct |
|
a = 7 or a = -7 |
|
a = -7 |
The absolute value is the positive magnitude of a particular number or variable and is indicated by two vertical lines: \(\left|-5\right| = 5\). In the case of a variable absolute value (\(\left|a\right| = 5\)) the value of a can be either positive or negative (a = -5 or a = 5).